Question

The area of the garden was 2¾yd². If the length is 1 ½ yd, find the width.

Answer 1

Answer:

Step-by-step explanation:

The area A of a rectangle of length L and width W is A = L*W.  Solving this for W, we get A/L.

Substituting 2 3/4 yd^2 for A and 1 1/2 yd for L, we get:

W = (2 3/4 yd)^2 / (1 1/2 yd)

This is equivalent to (11/4 yd^2 divided by (6/4 yd), or 11/6 yd.

The width of this garden is 11/6 yard, or 1 5/6 yard.

Answer 2

Answer:

11/6 or 1 5/6yards

Step-by-step explanation:

Area = Length x Width

2 3/4 = 1 1/2 w

11/4 = 3/2w  to change 2 3/4  into an improper fraction see this as 2 wholes plus 3/4.  Another name for 2 wholes is 8/4 then add the 3/4.  8/4 + 3/4 is 11/4.

Do the same for 1 1/2 which is 1 + 1/2 change 1 into 2/2 and add it to 1/2 which would be 3/2.

Now solve for x

(2/3) (11/4) = (3/2) (2/3) w  when I multiply 3/2 by its reciprocal of 2/3, I get the number 1 and 1 times w is just w.

22/12 =w.  I just multiplies the tops with the bottoms.  Now, divide the top and the bottom by 2 and you end up with 11/6.  If I divide 11 by 6, it will go into 11 one time with 5 left over.  The denominator remains 6.