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kramer
3 years ago
15

Solve for x: 3/4 + 2/3 + 8/9 = 2 x/36 Algebra 2

Mathematics
1 answer:
ioda3 years ago
7 0

Answer:

x = 11

Step-by-step explanation:

<u>Steps as below:</u>

  • 3/4 + 2/3 + 8/9 = 2 x/36
  • 3*9/4*9 + 2*12/3*12 + 8*4/9*4 = 2 x/36
  • 27/36 + 24/36 + 32/36 = 2 x/36
  • 83/36 = 2 x/36
  • 2 11/36 = 2 x/36
  • x= 11
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PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
sal works for a computer repair shop. he has determines that customers pay on average $150 for each computer they bring in. He p
Effectus [21]

Answer:

The answer is :

sal must repair 320 computers in a year to break even.

Step-by-step explanation:

The break even point in a business is the point at which the total costs and the total revenue in a business are equal.

In order to calculate sal's break even point, we will first of all calculate the total costs incurred during the business year, then using the selling price (repairing price), we will calculate how many computers will be repaired to reach the incurred cost. This is done as follows:

Rent per month = $2,000

∴ Rent for a year (12 months) = 2,000 × 12 = $2,400

Cost incurred in fixing each computer = $75

Priced charged for fixing each computer = $150

Next, since we know that sal requires $75 in parts and labor to fix a computer, we will calculate the net price charged for each computer fixed as follows:

Net price charged = Priced charged for fixing each computer - Cost incurred in fixing each computer

Net price charged = 150 - 75 = $75

Finally to calculate the break even point, we know the net income (net price charged) for each computer and the costs of rent for each year, therefore, we will divide the cost incurred by the net price charged, as follows:

break even point = cost of rent for one year ÷ net price charged

break even point = 24,000 ÷ 75 = 320 computers.

Therefore, by the time sal repairs 320 computers during the year, he must have covered the costs incurred in operations, every additional repair, becomes a profit.

3 0
3 years ago
-7 over 1 3rd written as a fraction is
m_a_m_a [10]

Answer: 22/3 I think

sorry if it’s wrong

7 0
2 years ago
Read 2 more answers
Expand and simplify (x + 11)(x + 11)
labwork [276]

Answer:

Expand: x² + 11x + 11x + 121

Simplify: x² + 22x + 121

Step-by-step explanation:

To expand this, you can use the FOIL technique:

First terms

Outer terms

Inner terms

Last terms

(x+11)(x+11)

F - x*x = x²

O - x*11 = 11x

I - 11*x = 11x

L - 11*11 = 121

Put these numbers together (expanded) to get:

x² + 11x + 11x + 121

Put the common terms together (simplify) to get:

x² + 22x + 121

Note:

Not sure if you need this info, but (x + 11)(x + 11) is the same as (x + 11)².

The numbers need to be in the order I put them in because you are supposed to place them in order greatest to least degree.

Hope it helps!

6 0
3 years ago
3a+2(4a-b)<br> please simplify this equation with processing
Alexeev081 [22]

\bf \colorbox{black} {\bf {\textcolor{blue}{topic= }{ \bf { \textcolor{orange}{mathematics= }{ \bf{ \textcolor{cyan}{answer = }}}}}}}

3a+2(4a-b)=

3a+8a-2b=

\bf \textcolor{green}{ \underbrace{11a - 2b}}

<h2>xLasersx✨</h2>
8 0
2 years ago
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