Answer:
15:17
Step-by-step explanation:
Since the triangle has a right angle, we may find the length of the unknown side using the trigonometric notations SOH CAH TOA where
SOA stands for
Sin Ф = opposite side/hypotenuses side
Cosine Ф = adjacent side/hypotenuses side
Tangent Ф = opposite side/adjacent side
With respect to ∠B given that ∠D=90°,
BD is the adjacent side
CB is the hypotenuse side
and DC is the opposite side
Hence Sin B = 15/17
27 divided by 3 = 9
9 times 5 = 45
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.
It follows from the definition of the derivative and basic properties of arithmetic. Let <em>f(x)</em> and <em>g(x)</em> be functions. Their derivatives, if the following limits exist, are
The derivative of <em>f(x)</em> + <em>g(x)</em> is then
