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VikaD [51]
1 year ago
8

__________ is the use of high energy radiation to kill cancer cells.

Chemistry
2 answers:
Ainat [17]1 year ago
5 0

Answer:

Radiation therapy is the use of high energy radiation to kill cancer cells.

Nadusha1986 [10]1 year ago
3 0

Answer:

Radiation Therapy.

Explanation:

Also known as radiotherapy, it uses high-energy radiation to damage and/or kill cancer cells.

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The free energy for the oxidation of glucose to CO2 and water is -686 kcal/mol, and the free energy for the reduction of NAD+ to
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Answer:

Most of free energy available from oxidation of the glucose remains in pyruvate.

Explanation:

The overall reaction of the process glycolysis is:

Glucose + 2 NAD⁺ + 2 ADP + 2 Pi ⇒ 2 Pyruvate + 2 NADH + 2 H⁺ + 2ATP

Glucose is oxidized to give 2 molecules of pyruvate and 2 molecules of NADH and ATP (Energy currency).

<u>Though the free energy of oxidation of glucose is high but only 2 NADH is formed because the most of the free energy that is being released from the oxidation of glucose remains in the pyruvate which is produced in the reaction and thus only 2 molecules are formed.</u>

6 0
3 years ago
Please help! I really don’t understand it
chubhunter [2.5K]

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C. It makes sure there is a balance inside the body

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0.000431 L<br><br> Express your answer as an integer.
Molodets [167]

A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

Now, converting 0.000431 L to decimal an integer as:

0.000431 L = 431\times 10^{-6} L

Since, 1 L = 10^{6} \mu L

So, 431\times 10^{-6} L\times \frac{10^{6 \mu L}}{1 L} = 431 \mu L.

Hence, the integer value for 0.000431 L is 431 \mu L[.


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3 years ago
Select the example of symbiosis, chosen from the list below that is best described by the statement shown.
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