For number 9 and 10 what do I put for the distance between the points?

What is the measure of EH!?!????? RUNNING OUT OF TIME

vladimir2022 [97]

I think the answer is B.

6 0

3 years ago

N the recursive formula f(n) = f(n - 1) + 5, the value of the previous term is represented by

eimsori [14]

F(n-1) = f(n) - 5, based off of the first one

3 0

3 years ago

Claire says the expression 8x’has three terms: 8, x, and 3. Is she correct? Explain.

KatRina [158]

Answer:

No

Step-by-step explanation:

No because the 8x^3 is all one term since it is not separated by any signs.

8 0

2 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

The stands at the soccer field can hold 40 people. The stands are 3/4 filled. Of the people in the stands, 5/6 are home team fan

AysviL [449]

It is given in the question that the stands of the soccer field has the capacity to hold 40 people. Also it is given that the stands of the soccer field is 3/4 filled.
Then,
The number of people in the stands = 40 * (3/4)
= 30
So 30 people are in the stands of the soccer field.
Now among the people present in the stands of the soccer field, 5/6 are home fans and the rest are fans of the away team.
Then,
Number of home team fans = 30 * (5/6)
= 25
So there are 25 home team fans present in the stand of the soccer field.

5 0

3 years ago