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Zinaida [17]
2 years ago
10

For number 9 and 10 what do I put for the distance between the points?

Mathematics
1 answer:
olga55 [171]2 years ago
4 0

Answer:

I have wrote just answers

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What is the measure of EH!?!????? RUNNING OUT OF TIME
vladimir2022 [97]
I think the answer is B.

6 0
3 years ago
N the recursive formula f(n) = f(n - 1) + 5, the value of the previous term is represented by
eimsori [14]
F(n-1) = f(n) - 5, based off of the first one
3 0
3 years ago
Claire says the expression 8x’has three terms: 8, x, and 3. Is she correct? Explain.
KatRina [158]

Answer:

No

Step-by-step explanation:

No because the 8x^3 is all one term since it is not separated by any signs.

8 0
2 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
3 years ago
The stands at the soccer field can hold 40 people. The stands are 3/4 filled. Of the people in the stands, 5/6 are home team fan
AysviL [449]
It is given in the question that the stands of the soccer field has the capacity to hold 40 people. Also it is given that the stands of the soccer field is 3/4 filled.
Then,
The number of people in the stands = 40 * (3/4)
                                                          = 30
So 30 people are in the stands of the soccer field.
Now among the people present in the stands of the soccer field, 5/6 are home fans and the rest are fans of the away team.
Then,
Number of home team fans = 30 * (5/6)
                                             = 25
So there are 25 home team fans present in the stand of the soccer field.
5 0
3 years ago
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