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scoray [572]
3 years ago
5

Which security risk is an example of malware?

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0
D. Worm! Viruses, worms, rasonware, Trojans, bonets, and adware are also some examples!
kirza4 [7]3 years ago
7 0
The answer is D. A, B, and C are not valid.
You might be interested in
1.
GREYUIT [131]
People who picked up vanilla cupcakes = 80% x 53 

<u> 80% x 53  = 0.8 x 53 = 42 people </u>(nearest whole number)

42 people picked vanilla cupcakes


Volume of a sphere = 4/3πr³

<u>4/3πr³ = 4/3π(7)³ = 1436.8 cm³</u>

The volume of the sphere is 1436.8 cm³
3 0
3 years ago
Read 2 more answers
What is the length of leg s of the triangle below?
Phoenix [80]

Answer:

option A

Step-by-step explanation:

take 45 degree as reference angle

using sin rule

sin 45 = opposite / hypotenuse

\frac{1}{\sqrt{2} } = s/8\sqrt{2}

\frac{1}{\sqrt{2} } *8\sqrt{2} = s

root 2 and root 2 gets cancel

8 = s

8 0
2 years ago
Hey guys I need help! I'm having so much trouble with understanding this...
Aleonysh [2.5K]
What part do you have trouble with
8 0
3 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
a club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes
seropon [69]

Answer:

1000(1/20000) +

300(2/20000) +

10(20/20000) +

=

1800/20000 = .09

Step-by-step explanation:

Each ticket purchased is expected to win 9 cents

Each ticket purchased cost 75 cents

If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.

4 0
3 years ago
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