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yan [13]
2 years ago
10

What is the coefficient of (3y^2 + 9)5

Mathematics
1 answer:
PtichkaEL [24]2 years ago
6 0

The coefficient of (3y² + 9)5 is <u>15</u>.

A polynomial is of the form a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ.

Here, x is the variable, aₙ is the constant term, and a₀, a₁, a₂, ..., and aₙ₋₁, are the coefficients.

a₀ is the leading coefficient.

In the question, we are asked to identify the coefficient of (3y² + 9)5.

First, we expand the given expression:

(3y² + 9)5

= 15y² + 45.

Comparing this to the standard form of a polynomial, a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² + ... + aₙ₋₁x + aₙ, we can say that y is the variable, 15 is the coefficient, and 45 is the constant term.

Thus, the coefficient of (3y² + 9)5 is <u>15</u>.

Learn more about the coefficients of a polynomial at

brainly.com/question/9071229

#SPJ1

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Step-by-step explanation:

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Draw a line representing the "rise" and a line representing the "run" of the line, State
Alexxx [7]

Answer:

The slope of the line m = 1

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

In the given graph

The points are ( 7,0) and ( 0, -7)

The slope of the line

            m = \frac{y_{2}- y_{1}  }{x_{2}-x_{1}  } = \frac{-7-0}{0-7} = \frac{-7}{-7} = 1

The equation of the straight line passing through the point (7,0) and slope m=1

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   y = x -7

   x - y -7=0

<u><em>Final answer:-</em></u>

The slope of the line m = 1

The equation of the straight line x -y -7=0

<u><em></em></u>

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