What number would you add to both sides of x^2+7x=4 to complete the square?

Mathematics

1 answer:

emmainna [20.7K]3 years ago

3 0

Answer:

49/4

Step-by-step explanation:

x^2+7x=4

Take the coefficient of x

Divide by 2

7/2

Then square it

(7/2) ^2 = 49/4

Add this to both sides of the equation to complete the square

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Triangle ABC has sides with lengths of 11, 18, and 8 units. Determine whether this triangle is a right triangle.

Arturiano [62]

Answer:

Not a right triangle.

Step-by-step explanation:

If this triangle is a right triangle, then the Pythagorean theorem would work on it. According to the Pythagorean theorem, $a^2+b^2=c^2$ , so c would always be greater than a or b. In this scenario, the greatest number here is 18, so c = 18. Since a or b don't matter if given both legs, we have the following equation that may or may not be equal: $8^2+11^2=18^2$ . We know 8 squared is 64, and 11 squared is 121, and 18 squared is 324. This means that $64+121=324$ according to the Pythagorean theorem, and since 64 + 121 = 185, and 185 does not equal 324, the Pythagorean theorem does not work and the triangle is not a right triangle.