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Liono4ka [1.6K]
3 years ago
7

plez help me it comes with 98 points ill even mark your answer as the brainliest plzz i really need the answer

Mathematics
2 answers:
Serga [27]3 years ago
8 0

Answer:

100 dollars per book

Step-by-step explanation:

1 divide

2 multiply

3 add

Keith_Richards [23]3 years ago
4 0

Answer:

a = 100

b = 5

Step-by-step explanation:

Just plug this into the equation it shows:

R(1) = (500 + (100)(1)) (50 - (5)(1))

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(3+1)²·3 plz help me
xxMikexx [17]

Answer:

Step-by-step explanation:

( 3+1)² * 3

= 4² * 3

= 16 * 3

= 48

6 0
3 years ago
Somebody help me with this?
trasher [3.6K]

Answer:

Zero's

Step-by-step explanation:

4 0
2 years ago
Solve the inequality -2/9b>-12
trapecia [35]

Answer:

1/2

Step-by-step explanation:

3 0
3 years ago
Can someone please help convert these so they have the same denominator??
ratelena [41]

The LCM of the denominators is 120. In other words, the denominators can multiply to 120.

3 * 40 = 120

40 * 2 = 80

Tigers: P = 80/120

24 * 5 = 120

24 * 4 = 96

Redbirds: P = 96/120

8 * 15 = 120

3 * 15 = 45

Bulldogs P = 45/120

60 * 2 = 120

60 * 1 = 60

Titans P = 60/120

Answer

Tigers: P = 80/120

Redbirds: P = 96/120

Bulldogs: P = 45/120

Titans: P = 60/120

5 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
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