Answer:
You can use subtraction
Step-by-step explanation:
$27.50 - $8.75 = $18.75 (cost of scarf)
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the gloves cost 27.50 dollars and if the scarf cost 8.75 dollrs more then that means that if we subtract that extra mount we should get the price of the scarf
if $18.75 is the cost of scarf and if gloves are $8.75 more then...
$18.75 (scarf) + $8.75 (extra $) = $27.50 (gloves)
Answer: units = 6198
Step-by-step explanation:
expected consumer demand is 5000, the units that must be planned given shrinkage percentage levels in different stages of the supply chain we have to use the trial and error method.
lets try 6200 units
6200 x 95% = 5890, 5890 x 96% = 5654.4, 5654.40 x 97% = 5484.768, 5484.768 x 96% = 5265.37728, 56265 x 95% = 5002.108416 ≈ 5002
6198 units
(6198 x 95% = 5888.10) (5888.10 x 96% = 5652.576) (5652.576 x 97% = 5482.99872) (5482.99872 x 96% = 5263.6787712) (5263.6787712 x 95% = 5000.4948326) ≈ 5000
using the same procedure for 6197 units the answer will be 4999.688041
units that should be produced to cover the demand of 5000 = 6198
Answer:
The expected number of graphing calculators that malfunctions within 3 months and need to be replaced is 915,000.
Step-by-step explanation:
Let <em>X</em> represents the number of graphing calculator that starts malfunctioning within 36 months of the purchase and needs to be replaced by a new one.
It is provided that <em>X</em> follows a normal distribution with a mean of 54 months and a standard deviation of 8 months.
Also, using the normal model it was determined that 1.22% of graphing calculator manufactured by Texas Instruments malfunctions and needs replacement.
That is,
P (<em>X</em>) = 0.0122
Texas Instruments has sold 75 million graphing calculators world- wide.
Compute the expected number of graphing calculators that malfunctions within 3 months and need to be replaced as follows:
E (<em>X</em>) = n × P (<em>X</em>)
= 75 × 10⁶ × 0.0122
= 915000
Thus, the expected number of graphing calculators that malfunctions within 3 months and need to be replaced is 915,000.
