Answer:
-1
Step-by-step explanation:
See the attachment for the polynomial long division. The constant in the quotient is -1.
_____
Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.
That could be a first guess in a "guess and check" solution approach.
<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).
<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2
Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.
80p=pr^2+p(2r)^2
80p=pr^2+4pr^2
80=r^2+4r^2
80=5r^2
16=r^2
r=4 for the smaller circle´s radius, and 8 is the larger circle´s radius.
Have a nice day, I hope this was helpful :D
Answer:


Step-by-step explanation:
Given


--- not -67

Required
Find q and r
Substitute values for d and b



Make q the subject

means that r is less than 8 but greater than or equal to 0
And r and q are integers.
Let 



No other true values of r and q can be gotten.
Answer:
x=8
Step-by-step explanation:
9x - 8 = 64 (being vertically opposite angles)
9x = 64 + 8
x=72/9
x=8
9x -8
9*8 -8
72-8
64