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3 years ago

Round 0.74 to the nearest tenth

Mathematics

2 answers:

Shalnov [3]3 years ago

6 0

The answer would be 0.7

Nimfa-mama [501]3 years ago

5 0

Answer:

Step-by-step explanation:

if the second number was over 5 then, you would have rounded it to .8, but it was only 4 so you round down.

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Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

Triangle PQR is reflected across a line, P = (4,–5), and P’ = (–4, –5). What is the line of reflection?

topjm [15]

-4,5. 4,5 that would be the answer it's like the oppiste

5 0

4 years ago

If f(x) = 5x + 4, which of the following is the inverse of (fx)?

lys-0071 [83]

Answer:

see explanation

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

y - 4 = 5x ( divide both sides by 5 )

$\frac{y-4}{5}$ = x

Change y back into terms of x

$f^{-1}$ (x) = $\frac{x-4}{5}$

3 0

3 years ago

∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices

Semenov [28]

Well you have to change the first number in ALL of the () so

(-1,1) = (1,1)

(-2,-1) = (2,-1)

(-1,0) = (1,0)

so your answer is d <span>(1, 1), B(2, -1), C(1, 0)</span>

7 0

3 years ago

Read 2 more answers

Find the equation of parabola

Oksana_A [137]

Answer:

somone in my class is literally a new York rat

Step-by-step explanation:

8 0

1 year ago