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Sindrei [870]
2 years ago
15

What equation is parallel to 3y = 6x-10 and passes through A(4,5)?

Mathematics
2 answers:
elena-s [515]2 years ago
7 0

Answer:

57?

Step-by-step explanation:

nikitadnepr [17]2 years ago
7 0
3y = 6x-10
y = 2x-10/3

The equation we are finding will have a gradient of 2 because it’s parallel. Therefore we need to find the y-intercept now.

When x=4, y=5,
y = 2x + c
5 = 8 + c
c = -3

Hence the equation is,
y = 2x-3
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Please help me with this question.
kow [346]
They are equivalent. combine like terms on the first one and 9x-4x+25 can be simplified to 5x+25.
6 0
2 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

4 0
2 years ago
150=3/5x what does x equal?
svetlana [45]

Answer:

250

Step-by-step explanation:

150/3=50

50*2=100

150+100=250

7 0
3 years ago
Read 2 more answers
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
2 years ago
What are the solutions of the quadratic equation4x*2 − 8x − 12 = 0 ?A) x = −1 and x = −3B) x = −1 and x = 3C) x = 1 and x = −3D)
blsea [12.9K]

The solutions for the given quadratic equation are x = -1 and x = 3. So, option B is correct.

<h3>What are the solutions to an equation?</h3>
  • The solutions to an equation are the one that satisfies the equation and makes it true.
  • There are different methods to solve an equation and find its solutions.
  • These solutions are also called zeros or roots of the equation.

<h3>Calculation:</h3>

The given equation is 4x² - 8x - 12 = 0

Since it is a quadratic equation, it has 2 roots or solutions.

On factorizing the given equation,

4x² - 8x - 12 = 0

⇒ 4x² - 12x + 4x -12 = 0

⇒ 4x(x - 3) + 4(x - 3) = 0

⇒ (4x + 4)(x - 3) = 0

According to the zero-product rule,

4x + 4 = 0 or x - 3 = 0

So, x = -4/4 = -1 or x = 3

Therefore, the solutions of the given equation are -1 and 3.

So, option B) x = -1 and x = 3 is correct.

Learn more about solving an equation here:

brainly.com/question/25678139

#SPJ4

5 0
1 year ago
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