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2 years ago

What equation is parallel to 3y = 6x-10 and passes through A(4,5)?

Mathematics

2 answers:

elena-s [515]2 years ago

7 0

Answer:

57?

Step-by-step explanation:

nikitadnepr [17]2 years ago

7 0

3y = 6x-10
y = 2x-10/3

The equation we are finding will have a gradient of 2 because it’s parallel. Therefore we need to find the y-intercept now.

When x=4, y=5,
y = 2x + c
5 = 8 + c
c = -3

Hence the equation is,
y = 2x-3

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Determine which situation(s) best describes operations with the numbers 4.58 and -0.145. Select all situations that apply.

saul85 [17]

Answer:

Real Numbers: Any number that can name a position on a number line is a real number. Every position on a number line can be named by a real number in some form.

An important property of real numbers is the Density Property. It says that between any two real numbers, there is always another real number.

Rational Numbers: Any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions.

An integer can be written as a fraction simply by giving it a denominator of one, so any integer is a rational number.

; ;

A terminating decimal can be written as a fraction simply by writing it the way you say it: 3.75 = three and seventy-five hundredths = , then adding if needed to produce a fraction: . So, any terminating decimal is a rational number.

A repeating decimal can be written as a fraction using algebraic methods, so any repeating decimal is a rational number.

Integers: The counting numbers (1, 2, 3, ...), their opposites (negative1, negative2, negative3, ...), and zero are integers. A common error for students in grade 7 is to assume that the integers account for all (or only) negative numbers.

Whole Numbers: Zero and the positive integers are the whole numbers.

Natural Numbers: Also called the counting numbers, this set includes all of the whole numbers except zero (1, 2, 3, ....)

Irrational Numbers: Any real number that cannot be written in fraction form is an irrational number. These numbers include the non-terminating, non-repeating decimals (pi, 0.45445544455544445555..., 2, etc.). Any square root that is not a perfect root is an irrational number. For example, 1 and 4 are rational because 1 = 1 and 4 = 2, but 2 and 3 are irrational-there are no perfect squares between 1 and 4. All four of these numbers do name points on the number line, but they cannot be written as fractions. When a decimal or fractional approximation for an irrational number is used to compute (as in finding the area of a circle), the answer is always approximate and should clearly indicate this.

Step-by-step explanation:

hope i helped

8 0

3 years ago

Hello, please help me out and add steps if you can!

BabaBlast [244]

Answer:

ldk

Step-by-step explanation:

sorry

3 0

2 years ago

Given the sequence, 26, 13, 6.5, ..... find a) the 10th term and b) the sum of the first 18 terms

Hunter-Best [27]

Answer:

a) 10th term is 0.051

b) The sum of first 18 terms of given sequence is 51.48

Step-by-step explanation:

We are given the sequence 26, 13, 6.5, ..... we need to find

a) 10th term

b) Sum of first 18 terms

Before solving we need to determine if the sequence is arithmetic or geometric

The sequence is arithmetic if common difference d is same.

The sequence is geometric if common ratio r is same.

Finding common difference d: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

Finding common ratio r : 13/26 =0.5, 6.5/13= 0.5

As common ratio is same so, the sequence is geometric.

a) Finding common difference: 13-26 = -13, 6.5-13= -6.5

As common difference is not same so, the sequence is not arithmetic.

a) 10th term

The formula to find 10th term is: $a_n=a_1r^{n-1}$

We have a₁=26 and r = 0.5 n=10

$a_n=a_1r^{n-1}\\a_{10}=26(0.5)^{10-1}\\a_{10}=26(0.5)^{9}\\a_{10}=0.051$

So, 10th term is 0.051

b) Sum of first 18 terms

The formula to find sum of geometric series is: $S_n=\frac{a(1-r^n)}{1-r}$

where a= 1st term, r = common ratio and n= number of terms

In the given sequence we have

a=26, r=0.5 and n=18

Finding sum of first 18 terms

$S_n=\frac{a(1-r^n)}{1-r}\\S_{18}=\frac{26(1-(0.5)^{18}}{1-0.5}\\S_{18}=\frac{26(0.99)}{0.5}\\S_{18}=\frac{25.74}{0.5}\\S_{18}=51.48$

So, sum of first 18 terms of given sequence is 51.48

6 0

3 years ago

Hiii! can someone please help me with my maths question

beks73 [17]

Step-by-step explanation:

a^2 + b^2 = c^2

(x+2)^2 + 4x^2 = (3x+4)^2

(x+2)(x+2)+ 4x^2= (3x+4)(3x+4)

x^2 + 2x + 2x + 4 + 4x^2 = 9x^2 + 12x + 12 x + 16

5x^2 + 4x + 4 = 9x^2 + 24x + 16

-4x^2 - 20x - 12 = 0

now we can use the quadratic formula

(-b±√(b²-4ac))/(2a)

I can't type all this so

.....

x = -0.697224362 or -4.302775638

AB can't be negative so it's the first one

so it's equals to 1.302775638

6 0

3 years ago

What’s 3х + 7>4х +2

Kipish [7]

Answer:

$x < 5$

Step-by-step explanation:

$3x + 7 > 4x + 2 \\ 7 - 2 > 4x - 3x \\ 5 > x$

$x < 5$

6 0

3 years ago