3 years ago

I can not figure out how to do this question and I need help please

1 answer:

6 0

$\bf \textit{quadratic formula}\\\\

\begin{array}{lcclll}
1x^2&-6x&+12&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}$

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