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dem82 [27]
3 years ago
9

I can not figure out how to do this question and I need help please

Mathematics
1 answer:
spayn [35]3 years ago
6 0
\bf \textit{quadratic formula}\\\\

\begin{array}{lcclll}
1x^2&-6x&+12&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
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How many factors does the algebraic expression 9xy have
lutik1710 [3]
It has 8 factors: 1, 9, x, y, 9x, 9y, xy, 9xy
5 0
3 years ago
Read 2 more answers
List from least to greatest<br> 4.1, 0.25, 0.042, 2.21
jolli1 [7]

Answer:

4.1, 2.21, 0.25,0.042

Step-by-step explanation:

you have to add a 0 onto the first one because it will bring it to be equal to most of the others

3 0
3 years ago
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(0.49+0.045)÷5 show steps to solve this
Rzqust [24]
Solve within parenthesis first so .49 +.045 =.535 so then divide by five which is .107
4 0
3 years ago
Read 2 more answers
PLEASE HELPP MEEEEE
pav-90 [236]
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.

Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11

Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
6 0
3 years ago
The diagram shows a right-angled triangle.
Alexus [3.1K]

Step-by-step explanation:

there is no diagram so I'm just going to guess this however

sin x = 6/9

sin x = 2/3

sin x = 0.67

x = sin inverse of 0.67

x = 42.1

8 0
2 years ago
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