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2 years ago

PLEASE HELP ASAP !!!!

Mathematics

1 answer:

murzikaleks [220]2 years ago

6 0

Answer:

Options 1 and 2

Step-by-step explanation:

Correct. The range of all linear functions without a restricted domain is the set of all real numbers.
Correct. The range of all linear functions without a restricted domain is the set of all real numbers.
Wrong. The exponential cannot take negative values.
Wrong. Quadratics do not have a range that is the set of real numbers.
Wrong. Quadratics do not have a range that is the set of real numbers.

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A special deck of cards has ten cards. Four are green (G), four are blue (B), and two are red (R). When a card is picked, the co

a_sh-v [17]

Answer:

{GT, GH, BT, BH, RT, RH};

1 /5;

Mutually exclusive ;

Not mutually exclusive.

Step-by-step explanation:

Given :

Green cards, G = 4

Blue cards, B = 4

Red cards, R = 2

For a coin toss :

{H, T}

A card is picked, then a coin is tossed :

Sample space :

{GT, GH, BT, BH, RT, RH}

2.) probability of picking a green card, then probability of landing a head on a coin toss

P(A) = number of required outcome / Total possible outcomes

P(A) = P(green card) * P(Head)

P(A) = (4 / 10) * (1/2)

P(A) = 4 /20

P(A) = 1/5

C.)

Both A and B are mutually exclusive, since both event A and event B cannot occur together, since both red and green cannot be picked during a single pick, this either a red is picked or green is picked, then they are A and B are mutually exclusive.

D.) Event A and C are not mutually exclusive, picking a green card, event A and picking a red or blue card, event B. Both event can happen simultaneously, hence, event A and B are not mutually exclusive.

6 0

3 years ago

I need help plsssss...........

ch4aika [34]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

system of linear equation
PEMDAS

<h3>let's solve:</h3>

since y is equal to both equation therefore we can substitute the value of y into the other equation

$\sf substitute \: the \: value \: of \: y : \\ \sf - x + 2 = 3x - 4$
$\sf add \: x \: to \: both \: sides : \\ \sf - x + x + 2 = 3x + x - 4 \\ \sf 4x - 4 = 2$
$\sf add \: 4 \: to \: both \: sides : \\ \sf xx - 4 + 4 = 2 + 4 \\ 4x = 6$
$\sf divide \: both \: sides \: by \: 4 : \\ \frac{4x}{4} = \frac{6}{4} \\ x = \frac{3}{2}$

let's figure out y

substitute the got value of x into the second equation: y=3*3/2 -4
simplify multiplication:9/2 -4
simplify division:4.5-4
substract:0.5 alternate form:y=½

3 0

3 years ago

If MN = x+4 and DE = 3x-2, find x. (More info in pic)

algol [13]

Answer: D) 10

============================================================

Explanation:

I'm assuming points M and N are midpoints of segments FD and FE respectively. If that's the case, then segment DE is twice as long compared to segment MN. We consider MN to be a midsegment.

So,

DE = 2*(MN)

3x-2 = 2*(x+4)

3x-2 = 2x+8

3x-2x = 8+2

x = 10

6 0

3 years ago

y=−2x+4 Complete the missing value in the solution to the equation. ( −2) Need it quick no explanation need.

Elodia [21]

Answer:

1 is missing value..... .....

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3 years ago

When asked to graph the line for y = 2/5x + 3, Mallory drew the line shown.

Helen [10]

Answer:

Step-by-step explanation:

Using desmos we can see that the slope is positive and increasing while Mallory made a negative slope.

5 0

3 years ago