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Mamont248 [21]
3 years ago
5

I need help on this

Mathematics
1 answer:
sweet [91]3 years ago
6 0
So basically you would take you your m which is 339 degrees greater than 3 so you would divide 339 by 3 and get 113 so your m= 113 degrees so for example the first question would be m<1 = 113 and so on so you would multiply 113 by the number it is greater than
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-5(x - 4) + 6 = 5(3x+4) -4
jenyasd209 [6]

Answer:

x=1/2

Step-by-step explanation:

-5(x - 4) + 6 = 5(3x+4) -4

WE APPLY DISTRIBUTIVE PROPERTY:

-5*x +5*4 + 6 = 5*3x +5*4 -4

-5x + 26 = 15x +20 -4

26 +4 -20=15x+5x

10=20x

x= 10/20

we have:

x=1/2

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3 years ago
At what point on the graph of y=2e^X -1 is the tangent line parallel to the line y= 5x -1
IgorLugansk [536]
Paralell has same slope
y=mx+b
m=slope
y=5x-1
when is the slope 5?

take the derivitive of 2e^x
f'(2e^x)=2f'(e^x)=2e^x

that is the slope
5=2e^x
divide both sides by 2
2.5=e^x
take the ln of both sides
ln2.5=x

when x=ln2.5 they are paralell
5 0
3 years ago
Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D?
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6 0
2 years ago
Read 2 more answers
A graph titled Monthly Sales and Advertising Costs has Advertising Costs (1,000 dollars) on the x-axis and sales (1,000 dollars)
ludmilkaskok [199]

Answer: The awnser is A,C,E

I just did it and got it right

4 0
3 years ago
Read 2 more answers
Simplify. (5x^3y^2+x^2-6x^2y^3) - (3x^2y^3-4y^3+7x^2)
Zanzabum

Answer:

Step-by-step explanation:

The initial expression is:

(5x^{3}y^{2}+x^{2}-6x^{2}y^{3})-(3x^{2}y^{3}-4y^{3}+7x^{2})

Using BEMDAS (Brackets - Exponents - Multiplication - Division - Addition -Subtraction), we first start with brackets:

5x^{3}y^{2}+x^{2}-6x^{2}y^{3}-3x^{2}y^{3}+4y^{3}-7x^{2}

Remember that if there is a negative sign, it will change the signs of the terms within the brackets.

Then, collecting like terms:

5x^{3}y^{2}-9x^{2}y^{3}+4y^{3}-6x^{2}

5 0
3 years ago
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