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1 year ago

Product of squre of x and cube of y

Mathematics

2 answers:

julsineya [31]1 year ago

6 0

Answer:

x²y³

Step-by-step explanation:

(x²) (y³) = x²y³

Hope it helps!

Have a nice day:)

Mashcka [7]1 year ago

4 0

❄ Hi there,

let us find the product of the square of x and the cube of y.

$\sf{The \ square \ of \ x: \ x^2}\\\sf{The \ cube \ of \ y: y^3}\\\sf{The \ product \ of \ the \ two: x^2y^3}$

The square of x means: x times x, or, as I said earlier, x².

The cube of y means: y times y times y, or, as I said earlier, $\sf{y^3}$ .

The product means: you multiply x² times y³.

❄

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Enter the sum of numbers as a product of their GCF. 75 + 30 The sum of the numbers as a product of their GCF is

Oksanka [162]

Answer: 75+30 = 15 x 7

Step-by-step explanation:

The given expression is 75+30 (=105) which defines the sum of 75 and 30.

Prime factorization of 75 and 30 are as below:

75 = 5 x 5 x 3

30 = 5 x 3 x 2

GCD (75,30) = 5x 3 = 15 [Note: GCD = Greatest common divisor]

Consider 75+30 = (15 x 5) + (15 x 2) [75 = 15 x 5 and 30= 15 x 2]

= 15 (5+2) [taking 15 as common ]

= 15 x (7)

(=105)

So, 75+30 which is sum of the numbers and it is expressed as 15 x 7 which a product of their GCF.

7 0

3 years ago

Using the order of operations rule, solve the following 12 divided by 2 plus 4 minus 2 times 3 equals ?

laiz [17]

Answer:

12 divided by 2 + 4 - 2 x 3 is 4

Step-by-step explanation:

I did 12 divided by 2 first which was 6 then added 4 subtracted it by 2 then multiplied it by 3 and got 4.

6 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

Mitch has a swimming pool in his backyard. The rectangular swimming pool has a volume of 243 m cubed. The length of the pool is

Maksim231197 [3]

Answer:

81 $m^{3}$

Step-by-step explanation:

Since the question states that the only difference would be the length of the neighbor's pool then this is basically a ratio problem. Therefore, since the question provides 3 values and one variable we can solve this using the Rule of Three which takes the diagonal values multiplies them together, and divides by the last sole value to get calculate the variable like so...

243 $m^{3}$ volume <=====> 9 m length

x $m^{3}$ volume <=====> 3 m length

(3* 243) / 9 = 81 $m^{3}$

Therefore, the volume of the neighbors pool will be 81 $m^{3}$

8 0

2 years ago

Find the measure of the indicated angle to the nearest degree

hjlf

Answer:

28°

Step-by-step explanation:

sin ? = 19/41

? = arcsin (19/41)

? = 28° (rounded to the nearest degree)

Answered by GAUTHMATH

8 0

2 years ago