Answer:
B. 38 Miles. add 13 and 25 what do you get? 38.
Step-by-step explanation:
Answer:
3howers
Step-by-step explanation:
Step-by-step exaplanation
Answer:
c:(0;+∞)
Step-by-step explanation:
Given the situation, that the square root function only allows you values above than "0" (not equal neither), then you must consider that every value above 0 belongs to it's domain.
Then, to express the domain, going from your most negative number, to your most possitive number (in this case all positive number, thats why we use infinite) you must use the parenthesis wich means, you are not considering the value (in this case 0), but the value right after it, to the next value that as we said before, is inifinite. Also remember, that when you express a domain, and use infinite (despite it's going to negative way, or possitive way, it also goes with parenthesis).
OK first let's check the x=1.5.





Oh my, that's called a depressed cubic, no

term. There's a formula for these very much like the quadratic formula but you're probably not quite old enough for that. Anyway,

is a solution, but that's not what they're asking. They are asking us to compare

with

and conclude

It turns out we did need all the rest of it. Save those brain cells, there's lots more math coming.
~~~~~~~~~~~~~~
I love it when the student asks for more. Here's the formula for a depressed cubic. I won't derive it here (though I did earlier today, coincidentally, but I'm probably not allowed to link to my Quora answer "what led to the discovery of complex numbers" from here). We use the trick of putting coefficients on the coefficients to avoid fractions.

has solutions
![x = \sqrt[3] { q - \sqrt{p^3 + q^2} } + \sqrt[3] {q + \sqrt{p^3 + q^2} } ](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%20q%20-%20%5Csqrt%7Bp%5E3%20%2B%20q%5E2%7D%20%7D%20%2B%20%5Csqrt%5B3%5D%20%7Bq%20%2B%20%5Csqrt%7Bp%5E3%20%2B%20q%5E2%7D%20%7D%20%0A%0A)
That's pretty simple, though sometimes we end up having to take the cube roots of complex numbers, which isn't that helpful. Let's try it out on

That's
so
![x = \sqrt[3] { 3 - \sqrt{(2/3)^3+9} } + \sqrt[3] {3 + \sqrt{(2/3)^3+9} }](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%203%20-%20%5Csqrt%7B%282%2F3%29%5E3%2B9%7D%20%7D%20%2B%20%5Csqrt%5B3%5D%20%7B3%20%2B%20%5Csqrt%7B%282%2F3%29%5E3%2B9%7D%20%7D%20)
![x = \sqrt[3] { 3 - \sqrt{753}/9 } +\sqrt[3]{3 + \sqrt{753}/9 }](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%203%20-%20%5Csqrt%7B753%7D%2F9%20%7D%20%2B%5Csqrt%5B3%5D%7B3%20%2B%20%5Csqrt%7B753%7D%2F9%20%7D)

Answer:
553.0 in³
Step-by-step explanation:
(please see attached for reference)
Assuming you are asked to find the volume,
the volume of the cylinder is given by
V = πr²h
where,
π=3.142
r = given as 4 inches
h = given as 11 inches
Substituting these values into the formula,
V = πr²h
V = 3.142 x 4² x 11
= 552.99
= 553.0 in³ (rounded to nearest tenth)