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alexgriva [62]
2 years ago
8

any sample proportion that is more than 1.96 standard errors from the popullation proportion will result in an

Mathematics
1 answer:
IRISSAK [1]2 years ago
3 0

Any sample proportion that is more than 1.96 standard errors from the population proportion will result in a confidence interval that includes p.

In frequentist records, a confidence interval is more than a few estimates for an unknown parameter. A self-belief interval is computed at a chosen self-belief stage; the ninety-five% self-assurance stage is maximum commonplace, however other tiers, which include ninety% or ninety-nine%, are now and again used.

The confidence stage is the share of instances you expect to get near the identical estimate if you run your test again or resample the populace in an identical manner.

The confidence c programming language includes the higher and lower bounds of the estimate you anticipate locating at a given stage of confidence.

As an instance, in case you are estimating a 95% self-belief c language around the mean share of lady toddlers born every 12 months primarily based on a random sample of babies, you may find a top certain of zero.56 and a decrease certain of zero.48. those are the top and decrease bounds of the self-belief c programming language. The self-assurance level is 95%.

Learn more about sample proportion here: brainly.com/question/24232216

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MariettaO [177]

Answer:

2x - 0.4x ;

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Yes

Step-by-step explanation:

Let number of miles = x

Arlene:

Double number of miles = 2 * x = 2x

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2x - 20% of 2x ;

2x - 0.4x

Raul:

Divides Number of miles by 5 ; x / 5

Multiplies result by 8 ;

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To know if expressions are equivalent :

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Using Arlene's expression:

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Using Raul's expression :

8x / 5

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5 0
3 years ago
A poll asks shoppers at the mall how many cups of water they typically drink in a day. The results of the poll are listed below.
juin [17]

Answer:

D 9.5

Step-by-step explanation:

Write data in increasing order.

3, 5, 5, 6, 6, 6, 7, 7, 8, 8, 8, 8, 8, 8, 9, 9, 10, 10, 10, 10, 11

Find the median

<u>3, 5, 5, 6, 6, 6, 7, 7, 8, 8,</u> 8, <u>8, 8, 8, 9, 9, 10, 10, 10, 10, 11</u>

Median is 8

Lower half of the data is : 3, 5, 5, 6, 6, 6, 7, 7, 8, 8,

First quartile is the median of the lower half of the data=6+6 /2 =6

Upper half of the data is: 8, 8, 8, 9, 9, 10, 10, 10, 10, 11

The Third quartile is the median of the upper half=9+10 / 2 = 9.5

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3 years ago
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Step-by-step explanation:

[1 -2]

[3 4]

We can obtain the determinant of the above matrix by doing the following:

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What is -10a to the 6th power over -9 simplified
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Step-by-step explanation:


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