Oh my, ummm if u go on slander and search that book name then type that page number it will give u all the answers, and the answers are probably at the back of the book <3
Answer:
From the problem, the answer to the equation is 5 1/10
Step-by-step explanation:
First, let's gather the information from the problem.
<em>a = 4 1/5 (also can be turned into 21/5)</em>
<em>b = 2 7/20 (also can be turned into 47/20)</em>
<em>c = 3 1/4 (also can be turned into 13/4)</em>
Now, plug in the numbers using the improper fractions.
21/5 - 47/20 + 13/4
Turn the denominators into the same number.
84/20 - 47/20 + 65/20
Subtract 84/20 and 47/20.
37/20 + 65/20
Add 37/20 and 65/20.
102/20 or 5 1/10
So, your answer to this equation is 5 1/10.
Answer: A
Step-by-step explanation:
Log_3(x(x + 24) = 4
log_3(x^2 + 24x) = 4
3^4 = (x^2 + 24x)
81 = x^2 + 24x
x^2 + 24x - 81 = 0
Continue from here.
Greetings!
To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.
<u>Proof:</u> <em>3-1=2, 5-3=2</em>
The first, consecutive, odd number: 
The second, consecutive, odd number: 
The third, consecutive, odd number: 
The fourth, consecutive, odd number: 
The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

Complete the operations inside the parenthesis:

Distribute the parenthesis (utilizing the distributive property)


Simplify both sides:

Add -6 and -x to both sides of the equation:


Divide both sides of the equation by 5:


If
is equal to -7:



The four numbers are:

I hope this helps!
-Benjamin