the absolute value of the product of the zeros of a is 
.
<u>Step-by-step explanation:</u>
Here we have , 
is a polynomial function of t, where k is a constant. Given that a(2) = 0 . We need to find the absolute value of the product of the zeros of a . Let's find out:
Equation every factor of a(t) to zero we get:
⇒ 
⇒ 
⇒ 
But , t=2 So , 
. Now , the absolute value of the product of the zeros of a is :
⇒ 
⇒ 
⇒
Therefore, the absolute value of the product of the zeros of a is .
1. a= 60 (vertically opposite angles)
b= 360-(60+60)=240/2= 120 (angles at a point)
c= 120 (vertically opposite angles with b)
2. c= 90-40= 50 (vertically opposite angles)
b=a=360-90-90=180/2=90 (angles at a point)
3. a= 180-52-51= 77 (angles on a straight line)
b=52 (angles at a point)
d=51 (angles at a point)
c=77 (angles at a point)
4. a= 60 (vertically opposite angles)
b= 360-(60+60)=240/2= 120 (angles at a point)
c= 120 (vertically opposite angles with b)
e=65
d=f= 360-65-65=230/2=115
h=55
i=g=360-55-55=250/2=125
5. b=163
a=90
e=70
d=360-70-70=220/2=110
c=360-163-163=34/2=17
Hope this helps!
M=slope
b=y-intercept
y and x are coordinates
hope this helps, that is a much as I can give you with this little of information
Yes, you would try to simplify the equation as much as possible in order to get the variable.
Answer:
a
Step-by-step explanation:
(√12 + 6)(-√8 -√2) = (√3×4 + 6)( -√2×4 -√2) =
(2√3 + 6)( -2√2 - √2) = (2√3 + 6)(-3√2) = -6√6 - 18√2
