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3 years ago

What is the mean and median of the lengths . 10,31,36,36,38,42,47,48,49,and 52

Mathematics

2 answers:

Olin [163]3 years ago

4 0

Answer:

$Mean = 38.9$ $Median = 40$

Step-by-step explanation:

When you find mean, you must add all the numbers together then divide by the amount of numbers.

$10+31+36+36+38+42+47+48+49 + 52$

$==> 389$

There are 10 numbers.

$389 / 10$

$==> 38.9$

To find median, you have to either find the middle number or find the two numbers that makes it equal. Since this range set is even, we use the second option.

$(x + y ) / 2$

$38 + 42$

$==> 80$

Divide by 2

$80 / 2$

$==> 40$

kipiarov [429]3 years ago

4 0

Answer:

38.9 and 40

Step-by-step explanation:

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Compare fractions using benchmarks

Vadim26 [7]

You can compare fractions by using the benchmark fraction of 1/2. To use this in order to make comparisons, you will need to look carefully at what the numerator and The denominators are in a fraction. If the top number, the numerator is less than half of the denominator, then the fraction would be less then the benchmark 1/2. If the numerator is more than half of the denominator then the fraction would be more than the benchmark 1/2. For example, 3/4 is more than 1/2 because the numerator of three is more than half of the denominator 4.

7 0

3 years ago

if the first 15 sandwiches sold at a restaurant one day, 9 were club sandwiches. at the same rate, how many sandwiches would hav

MaRussiya [10]

Answer:

54 I think

Step-by-step explanation:

I just did 15 divided by 9 and got 5/3 and then did 90 divided by 5/3 and got 54

6 0

3 years ago

I need help please ^^

Vaselesa [24]

Answer:

see below

Step-by-step explanation:

Usually, we're concerned about the relationship of y to x. Here, the question is asking you to consider the relationship of x to y.

The easiest way to find the answer to this one is to check the given explanations to see which is true. You can pretty much ignore the first row of the table and just look at the second row where x=5 and y=15.

it is NOT TRUE that x is 3 times y (5 is not 3 times 15)
it is TRUE that x is 1/3 of y (5 is 1/3 of 15)
it is NOT TRUE that x is 5 times y (5 is not 5 times 15)
it is NOT TRUE that x is 1/5 of y (5 is not 1/5 of 15)

_____

If you know your multiplication tables, you know that 15 = 3×5, so ...

5 = 15/3

5 = (1/3) × 15

The relationship of these numbers should not be a mystery.

4 0

3 years ago

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the school in ho

Ede4ka [16]

Solution:

we are given that

A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the schoo. The order of selection does not matter.

As we know

6 teacheras can be selected out of 30 teacher in ${30}_C_6$ ways.