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Anton [14]
4 years ago
14

a square pyramid has a base with a side length of 4 feet and lateral faces with heights of 3 feet. whay is the lateral area of t

he pyramid?
Mathematics
1 answer:
Nastasia [14]4 years ago
3 0
The answer would be 6 because you need to multiply the L by the H divided by to: 4x3+12    12/2  +6

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Solve for x write the smaller solution first and the larger solution second. Round to two decimal places (x+8)^2-7=0
siniylev [52]

Answer:

x ≈ - 10.65, x ≈ - 5.35

Step-by-step explanation:

Given

(x + 8)² - 7 = 0 ( add 7 to both sides )

(x + 8)² = 7 ( take the square root of both sides )

x + 8 = ± \sqrt{7} ( subtract 8 from both sides )

x = - 8 ± \sqrt{7} , thus

x = - 8 - \sqrt{7} ≈ - 10.65

x = - 8 + \sqrt{7} ≈ - 5.35

4 0
3 years ago
What is 7) 4x -2(3x + 7) <br>​
lapo4ka [179]

4x -2(3x+7)

Use the distributive property:

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Combine like terms:

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4 0
4 years ago
Solve the following equation for g.<br> Rg=m+h^2g
marshall27 [118]

Answer:

G=m/r-h^2

Step-by-step explanation:

move all the terms to the left side and set equal to zero. Then set each factor equal to zero. Hope this helps!

4 0
3 years ago
i need answers by tonight or the morning. its due tomarrow and im scarred to ask the teacher what to do.
kompoz [17]
I’ll explain part A and you can apply it to the other parts. The functions f(x), g(x), and m(x) are all equivalent to the given polynomials. So when it asks for f(x) + [g(x) - m(x)] you plug them in. The answer to Part A is 3x^2 +5x - z + [5x^2-3x+z - 2x^2 - 2x]. Combine the like terms (3x^2+5x^2-2x^2 = 6x^2 (because 3+5-2=6)) and so on until you’ve simplified it as much as possible!
4 0
3 years ago
If two tangent segments to a circle share a common endpoint outside a circle, then the two segments are
matrenka [14]

If two tangent segments to a circle share a common endpoint outside a circle, then the two segments are congruent. This is according to the intersection of two tangent theorem. The theorem states that  given a circle, if X is any point within outside the circle and if Y and Z are points such that XY and XZ are tangents to the circle, then XY is equal to XZ.

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4 0
4 years ago
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