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lidiya [134]
4 years ago
13

} " alt=" \sqrt{ \frac{3}{16} } " align="absmiddle" class="latex-formula">
Rational or irrational?
Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
7 0
Hello!
When you have a non-exact root (irrational number)

\sqrt{ \frac{3}{16} } \to  \frac{ \sqrt{3} }{ \sqrt{16} } \to  \boxed{\boxed{\frac{ \sqrt{3} }{4} }}\Longleftarrow(irrational\:number)\end{array}}\qquad\quad\checkmark
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Samir ran for 10 minutes, stopped and stretched for 5 minutes, walked for 20 minutes, and ran for another 15 minutes.
vfiekz [6]

Answer: Samir stopped and stretched for 5 minutes.

8 0
3 years ago
What is the sum of the polynomials? (8x2-9y2-4x)+(x2-3y2-7x)
White raven [17]
The sum of the polynomials (8x²-9y²-4x)+(x²-3y²<span>-7x) is:

 1. You must add the terms whose variables and exponents are the same. 
 2. Let's rewrite the polynomials:
</span>
 (8x²-9y²-4x)+(x²-3y²-7x)
 8x²-9y²-4x+x²-3y²-7x
 (8+1)x²+(-4-7)x+(-9-3)y²

 3. Therefore, the result is:

 9x²-11x-12y²

 3. <span>What is the sum of the polynomials?

 The answer is: </span>9x²-11x-12y²
3 0
3 years ago
Complete this item.
Anika [276]

Answer:

Given: An Angle in the figure is right angle. Its measure = 90°

So,

∠2 = 90° ( vertically opposite angles are equal )

∠1 + ∠2 = 180° ( Linear Pair )

∠1 = 180 - 90

∠1 = 90°

So, ∠1 and ∠2 are

Right angles because measure of both angles are 90°.

Adjacent angles because both a common arm and a common vertex.

Supplementary angles because sum of both angles is 180°.

Step-by-step explanation:

5 0
3 years ago
(2h3 + 6h) + (3h3 - 7h - 3) standard form sum or difference.​
worty [1.4K]

Answer:

5h^3- h - 3

Step-by-step explanation:

Given

(2h^3 + 6h) + (3h^3 - 7h - 3)

Required

Standard form

We have:

(2h^3 + 6h) + (3h^3 - 7h - 3)

Remove bracket

(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 6h + 3h^3 - 7h - 3

Collect like terms

(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 3h^3+ 6h  - 7h - 3

(2h^3 + 6h) + (3h^3 - 7h - 3) = 5h^3- h - 3

Hence, the standard form is:

5h^3- h - 3

3 0
3 years ago
This figure is made up of a triangle and a semicircle.
ArbitrLikvidat [17]
9.382 vifkvp unit rigging
7 0
3 years ago
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