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2 years ago

The graphs below have the same shape. What is the equation of the red graph?

Mathematics

1 answer:

VARVARA [1.3K]2 years ago

5 0

Answer:

$G(x) = x^{3} -1$

Step-by-step explanation:

The red graph is the blue graph translated 1 unit down, so the answer is A.

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What is the value of x? Enter your answer in the box (Please hurry)

GaryK [48]

Answer:

$\large\boxed{x=20}$

Step-by-step explanation:

The whole triangle and small triangle are similar (AA). Therefore the sides are in proportion:

$\dfrac{5x+10+10}{10}=\dfrac{121+11}{11}$

$\drac{5x+20}{10}=\dfrac{132}{11}$ cross multiply

$11(5x+20)=(10)(132)$ use distributive property

$(11)(5x)+(11)(20)=1320$

$55x+220=1320$ subtract 220 from both sides

$55x=1100$ divide both sides by 55

$x=20$

7 0

4 years ago

Larry harvested 4/5 of his crops already he is able to harvest 1/10 of the crops per day how many days will it take for Larry to

Lera25 [3.4K]

Answer:

2 days

Step-by-step explanation:

there is still 1/5 of his crops that need to be harvested. to see how many days that will take divide that amount and see how many 1/10 fit into it. 1/10+ 1/10 = 2/10 which is also 1/5 so it will take 2 days.

5 0

3 years ago

Jason earns 5% commission as a salesperson. He sold a lawn mower that cost $90. How

mr Goodwill [35]

Jason earns $4.50 as commission

5 0

3 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$