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Rzqust [24]
2 years ago
6

ABIGAIL ORDERS A LARGE 2 TOPPING PIZZA FOR $14 AND A MEDIUM 1 TOPPING PIZZA FOR $10. IF ALL COST OF A MEDIUM PIZZA ARE 80% OF A

SIMILAR LARGE PIZZA, FIND THE PRICE OF A LARGE PLAIN CHEESE PIZZA AND THE COST OF EACH PIZZA TOPPING.
Mathematics
1 answer:
geniusboy [140]2 years ago
6 0
She shouldn't. She can get a 2 topping pizza for $7.99 at Pizza Hut instead.
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HURRY!! 8.1=8w- 17.5. Solve for w​
jasenka [17]
W= 3.2

Need explaining?
5 0
2 years ago
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Given the following functions f(x) and g(x), solve f over g(−4) and select the correct answer below:
marishachu [46]
\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\f(x)=4x-4;\ g(x)=x-1\\\\f(-4)=4\cdot(-4)-4=-16-4=-20\\\\g(-4)=-4-1=-5\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{-20}{-4}=4
5 0
3 years ago
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What is the degree of the function f(x)=x⁴-5x+8+x²?​
DENIUS [597]

First put it in decreasing power according to x.

x^4-5x+8+x^2

=x^4+x^2-5x+8

Now this question is asking what is the highest degree of x you see in this function.

4 of course.

Therefore the answer to his question is degree of 4.

Done!

7 0
3 years ago
Reduce to simplest form.<br> -7/12 + 3/8<br> (They are fractions)
denpristay [2]

Answer:

-5/24

Step-by-step explanation:

You first change -7/12 to -14/24, and 3/8 to 9/24 so they have the same denominator. You then do -14/24 + 9/24. That will be the same as the opposite of the answer to 14/24 - 9/24.

14/24 - 9/24 = 5/24

-5/24

4 0
3 years ago
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Olegator [25]

Answer:

b+6

Problem:

If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?

Step-by-step explanation:

We are given (b+c)/2=8 and d=3b-4.

We are asked to find (c+d)/2 in terms of variable, b.

We need to first solve (b+c)/2=8 for c.

Multiply both sides by 2: b+c=16.

Subtract b on both sides: c=16-b

Now let's plug in c=16-b and d=3b-4 into (c+d)/2:

([16-b]+[3b-4])/2

Combine like terms:

(12+2b)/2

Divide top and bottom by 2:

(6+1b)/1

Multiplicative identity property applied:

(6+b)/1

Anything divided by 1 is that anything:

(6+b)

6+b

b+6

3 0
2 years ago
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