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2 years ago

What would the pH of a solution that had a hydroxide ion concentration of 1 x 10-2 M be?

Chemistry

1 answer:

Y_Kistochka [10]2 years ago

8 0

Taking into account the definition of pH and pOH, the pH of the solution is 12.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

A solution had a hydroxide ion concentration of 1×10⁻² M. In other words [OH⁻]= 1×10⁻² M.

Replacing in the definition of pOH, it is calculated as:

pOH= - log (1×10⁻² M)

Solving;

Replacing in the relationship established between pH and pOH, the pH can be calculated as:

pH + 2= 14

Solving:

pH= 14 - 2

In summary, the pH of the solution is 12.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

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Hey can someone help me and show work please

Ivahew [28]

Answer: 2.54g

Explanation:

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1mole (34g) of H2O2 contains 6.02x10^23 molecules

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4 years ago

A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Cel

Mariulka [41]

Answer:

T₂ = 182 K

Explanation:

Given that,

Initial pressure, P₁ = 120 kPa

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{80\ kPa\times 273}{120\ kPa}\\\\T_2=182\ K$

So, the new temperature is equal to 182 K.

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3 years ago

The gas in a balloon occupies 2.25 L at 298 K and 300 kPa. At

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If a gas in a balloon occupies 2.25 L at 298 K and 300 kPa, the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.

<h3>How to calculate temperature?</h3>

The temperature of an ideal gas can be calculated using the following formula:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume
T1 = initial temperature
T2 = final temperature

According to the information given in this question;

P1 = 300kpa = 2.96 atm
P2 = 2.17 atm
V1 = 2.25L
V2 = 3.50L
T1 = 298K
T2 = ?

2.96 × 2.25/298 = 2.17 × 3.5/T2

0.022T2 = 7.595

T2 = 7.595 ÷ 0.022

T2 = 345.23K

Therefore, if a gas in a balloon occupies 2.25 L at 298 K and 300 kPa. the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.

Learn more about temperature at: brainly.com/question/11464844

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2 years ago