Answer : The number of bonding electrons and the number of non-bonding electrons are (4, 18).
Explanation :
The number of bonding electrons and non-bonding electrons in the structure of 
is determined by the Lewis-dot structure.
Lewis-dot structure : It tell us about the number of valence electrons of an atom within a molecule and it is also shows the bonding between the atoms of a molecule and the lone-pair of electrons.
In the given structure, 'Xe' is the central atom and 'F' is the terminal atom.
Xenon has 8 valence electrons and fluorine has 7 valence electrons.
Total number of valence electrons in = 8 + 2(7) = 22 electrons
From the Lewis-dot structure, we conclude that
The number of electrons used in bonding = 4
The number of electrons used in non-bonding (lone-pairs) = 22 - 4 = 18
Therefore, the number of bonding electrons and the number of non-bonding electrons are (4, 18).
The Lewis-dot structure of is shown below.
Answer:
Explanation:
Law of Conservation of Mass: The law that states that matter cannot be created nor destroyed
Ex: Kelly ran across the room and bumped into her brother, pushing him to the floor. The kinetic energy she possessed because of her movement was transferred to her brother, causing him to move.
Answer:
metals
Explanation:
Approximately three-quarters of all known chemical elements are metals. The most abundant varieties in the Earth's crust are aluminum,... Gold (Au), chemical element, a dense lustrous yellow precious metal of Group 11 (Ib), Period 6, of the periodic table.
Mass = mole x molar mass
Explanation:
The mole of the substance used in the bakanced eqn multipled by its molar mass equals to Its mass
Answer:
The pH of the buffer is 7.0 and this pH is not useful to pH 7.0
Explanation:
The pH of a buffer is obtained by using H-H equation:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>The pKa of acetic acid is 4.74.</em>
<em>[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles</em>
<em>[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles</em>
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Replacing:
pH = 4.74 + log [0.1779mol] / [0.001mol]
<em>pH = 6.99 ≈ 7.0</em>
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The pH of the buffer is 7.0
But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,
this pH is not useful to pH 7.0
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