Answer:
A decrease in the total volume of the reaction vessel (T constant)
Explanation:
- Le Châtelier's principle predicts that the moles of H2 in the reaction container will increase with a decrease in the total volume of the reaction vessel.
- <em><u>According to the Le Chatelier's principle, when a chnage is a applied to a system at equilibrium, then the equilibrium will shift in a way that counteracts the effect causing it.</u></em>
- In this case, a decrease in volume means there is an increase in pressure, therefore the equilibrium will shift towards the side with the fewer number of moles of gas.
Answer:
1) acetylide
2) enol
3) aldehydes
4) tautomers
5) alkynes
6) Hydroboration
7) Keto
8) methyl ketones
Explanation:
Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.
Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.
The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.
Answer:
B
Explanation:
the candle is hot so the first energy form should be heat. u could now just eliminate the rest but for further notice. the heat melts the wax in the candle, which is a physical change but also the thread is burning out which is a chemical change then light follows
Run clothes washer only when its full
<h3>
Answer:</h3>
112.08 mL
<h3>
Explanation:</h3>
From the question we are given;
- Initial volume, V1 = 100.0 mL
- Initial temperature, T1 = 225°C, but K = °C + 273.15
thus, T1 = 498.15 K
- Initial pressure, P1 = 1.80 atm
- Final temperature , T2 = -25°C
= 248.15 K
- Final pressure, P2 = 0.80 atm
We are required to calculate the new volume of the gases;
- According to the combined gas law equation;

Rearranging the formula;

Therefore;


Therefore, the new volume of the gas is 112.08 mL