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Sergeu [11.5K]
2 years ago
12

A car is being tested on a track. The driver approaches the test section at a speed of 28 m s−1. He then accelerates at a unifor

m rate between two markers separated by 100 m. The car reaches a speed of 41 m s−1.
Physics
1 answer:
dedylja [7]2 years ago
7 0

The uniform acceleration of the car is 4.485 m/s².

<h3>Acceleration of the car</h3>

The uniform acceleration of the car is calculated as follows;

v² = u² + 2as

a = (v² - u²)/2s

where;

  • v is final velocity = 41 m/s
  • u is initial velocity = 28 m/s
  • s is distance = 100 m
  • a is acceleration = ?

a = (41² - 28²)/(2 x 100)

a = 4.485 m/s²

Thus, the uniform acceleration of the car is 4.485 m/s².

Learn more about uniform acceleration here: brainly.com/question/2505743

#SPJ1

You might be interested in
The hydrocarbon used to manufacture foam plastics is called styrene. Analysis shows composition to be 92.25% C and 7.75% H. Anal
zhannawk [14.2K]

Answer:

molecular formula = C_{8} H_{8}

Explanation:

Given data

c = 92.25%

H = 7.75%

molar mass = 104 g/mol

to find out

the empirical and molecular formula for styrene

solution

we know that

styrene 1 g contain = 0.9225 g C and 0.0775 g H

so

C = 104 × 0.9225 g / 12 g/mol

C = 7.995 mol = approx 8 mol

and

H = 104 × 0.0775 g / 1 g/mol

H = 8.06 mol = approx 8 mol

so we say that 1 mole of styrene  have 8 mole of C and H

so

molecular formula = C_{8} H_{8}

8 0
4 years ago
A motorcycle is capable of accelerating at 1.5 m/s2. Starting from rest, how far can it travel in 0.5 seconds?
Helen [10]
Answer:
Here,
Initial velocity(u)=0 m/s
acceleration(a)=1.5m/s
time(t)=0.5s
Now,
distance covered(s)=ut+(1/2)at^2
                            =0*0.5+(1/2)*1.5*0.5*0.5
                             =0+(1/2)*0.375
                             =0+0.1875
                             =0.1875(nearly 0.19)
Hence,0.19 is correct answer.
                                       

6 0
4 years ago
A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the
Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0
3 years ago
Using two spring scales, students pull on opposite sides of a dynamic cart at rest. 7 Newtons of force is pulling left and 5 New
kirill [66]

Answer:

The cart will accelerate to the left

Explanation:

The cart is initially at rest. In order to understand its motion, we should consider the net force acting on the cart. We have two forces acting on it:

- A force of 7 N to the left

- A force of 5 N to the right

Therefore, the net force is

F=7 N -5N=2 N

in the direction of the stronger force (so, to the left).

According to Newton's second law:

F=ma

a net force different from zero produces an acceleration of the object, in the same direction as the net force. Therefore, the cart will accelerate to the left.

7 0
3 years ago
The displacement of particle moving along on x axis is given by x = 18t + 5.0t^2, where x is in meters and t is in seconds Calcu
Masja [62]

Answer:

38 m/s

43 m/s

Explanation:

x = 18t + 5.0t²

The instantaneous velocity is the first derivative:

v = 18 + 10.t

At t = 2.0:

v = 18 + 10.(2.0)

v = 38 m/s

The average velocity is the change in position over change in time.

v = Δx / Δt

v = [ (18t₂ + 5.0t₂²) − (18t₁ + 5.0t₁²) ] / (t₂ − t₁)

Between t = 2.0 and t = 3.0:

v = [ (18(3.0) + 5.0(3.0)²) − (18(2.0) + 5.0(2.0)²) ] / (3.0 − 2.0)

v = [ (54 + 45) − (36 + 20.) ] / 1.0

v = 99 − 56

v = 43 m/s

6 0
3 years ago
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