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spin [16.1K]
2 years ago
12

If the object is placed 6 cm from a concave mirror the image distance 12 cm what is the image discige of the objects move from t

he original position to 1 cm from the mirror
Physics
1 answer:
Alika [10]2 years ago
6 0

Answer:

The image distance is -9.3cm.

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An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction
Allisa [31]

In this collision, 1/2 of the initial kinetic energy of the first glider is converted into thermal energy.

<h3>In plain English, what is kinetic energy?</h3>

An object's strength as a result ofstrength an object has as a result or motion is known as kinetic energy. Toorder to accelerate an object, a force must be applied. Applying force requires effort on our part. When the work is done, power is transported to the thing, which causes it to move at the athe new, constant pace.

<h3>What does kinetic energy mean, or what are some instances?</h3>

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8 0
1 year ago
Electricity and magnetism
stellarik [79]

Answer:

Electricity is which is possessed by the flow of electrons.

Magnitism is the process in which the magnet attract the things which consist magnetic substance.

6 0
2 years ago
A torsion-bar spring consists of a prismatic bar, usually of round cross section, that is twisted at one end and held fast at th
ra1l [238]

Answer:

d₁ = 0.29 in

d₂ = 0.505 in

Explanation:

Given:

T = 1500 lbf in

L = 10 in

x = 0.5 L = 5 in

T_{1} =\frac{T(L-x)}{L} =\frac{1500*(10-5)}{10} =750lbfin

First case: T = T₁ + T₂

T₂ = T - T₁ = 1500 - 750 = 750 lbf in

If the shafts are in series:

θ = θ₁ + θ₂

θ = ((T₁ * L₁)/GJ) + ((T₂ * L₂)/GJ)

Second case: If d₁ ≠ d₂

θ = ((T₁ * L₁)/GJ₁) + ((T₂ * L₂)/GJ₂) = 0 (eq. 1)

t₁ = t₂

\frac{16T_{1} }{\pi d_{1}^{3}  } =\frac{16T_{2} }{\pi d_{2}^{3}  } (eq. 2)

T₁ + T₂ = 1500 (eq. 3)

θ₁ first case = θ₁ second case

Replacing:

\frac{750*5}{G(\frac{\pi }{32})*0.5^{4}  } =\frac{T_{1}*3.7 }{G(\frac{\pi }{32})*d_{1} ^{4}  }\\T_{1} =16216d_{1} ^{4}

The same way to θ₂:

\frac{750*5}{G(\frac{\pi }{32})*0.5^{4}  } =\frac{T_{2}*6.3 }{G(\frac{\pi }{32})*d_{2} ^{4}  } \\T_{2} =9523.8d_{2} ^{4}

From equation 2, we have:

d₁ = 0.587 * d₂

From equation 3, we have:

d₂ = 0.505 in

d₁ = 0.29 in

7 0
3 years ago
A 5​-gram ​[g] rubber ball is released from a height of 8 meters​ [m] above a flat surface on the moon. Gravitational accelerati
Neko [114]

Answer:

v = 5.0911 m/s

Explanation:

See it in the pic.

6 0
3 years ago
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Students in a science class were given a box of materials and asked to use the materials to demonstrate that moving charges crea
KiRa [710]

Answer:

what is it

Explanation:

did you get it?

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3 years ago
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