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Serhud [2]
2 years ago
5

What is the point-slope form of a line with slope that contains the point (-2, 1)?

Mathematics
1 answer:
Leya [2.2K]2 years ago
8 0

Answer:

d; y - 1 = 4/5(x + 2)

Step-by-step explanation:

the equation for a point-slope form line is y - y1 = m(x - x1)

plug in the points and you will get your answer

y - 1 = 4/5(x + 2)

that is your answer

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Using the graph, determine the equation of the circle
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Answer:.

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Well if you look at the graph and first look at the

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3 years ago
If there is a ratio of 3 to 2 what is the ratio of 3if the total is 30
xxMikexx [17]
45 will be the answer of 3 because 30 divide in 2 is 15. and 15x3 is 45.
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4 years ago
Solve for x in the equation X2-12x+59 = 0.
Slav-nsk [51]

Answer:

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A -708

7 0
3 years ago
A billboard is 2.5 times as long as it is wide.The area of the billboard is 2,250 ft.A scale drawing is made of the billboard,an
GaryK [48]
Width = w
Length = 2.5w

Area of Rectangle: Width × Length
w (2.5w) = 2250
2.5w^2 = 2250
w^2 = 2250/2.5 = 900
w = Sq rt of 900 = 30
l = 75

Ratio of inches to ft
x/30 = 160/2250
cross multiply: 2250x = 160 × 30
2250x = 4800
x = 4800/2250 = 2.13333...

length
x/75=160/2250
2250x = 75(160)
2250x = 12,000
x= 12,000/2250
x = 5.3333...

scale is 2.13" × 5.33"
3 0
4 years ago
Read 2 more answers
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
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