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hjlf
3 years ago
14

6. Find the mode of the set of data: 55, 56, 45, 51, 60, 53, 63, 70, 62, 58, 63

Mathematics
2 answers:
neonofarm [45]3 years ago
5 0

(6) Mode is 63 (occurs two times)

(7)

EHS 52 = 13x4

WHS 65 = 13 x 5

EHS will have 4 rows of 13 each

WHS will march in 5 rows of 13 each

Grace [21]3 years ago
3 0

6. 63(Could have counted wrong. Mode is the number that appears the most in a set of data)

7. Couldn't solve sorry!

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What’s the answer to question 3?
attashe74 [19]

Answer: The mean is <em>14</em> and the median is <em>14.5</em>

Step-by-step explanation:

To find the mean, add up all of the numbers in the series and divide by the amount of numbers in the series. In this case, the answer comes out to 14.

For the median, you put the numbers in order of least to greatest, as they are listed in the question. You then cross out a number from the left, then a number from the right, one at a time until you are left with either one middle number, or in this case two middle numbers. In this case you are left with 13 and 16. You then find the average of the two middle numbers, which in this case is 14.5

Hope this helps!

7 0
3 years ago
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You want to do a quick estimate to the ones place of the sum of the following set of data. Pick the correct estimation.
frez [133]

Answer:16

Step-by-step explanation:

16

3.5 - 4

6.7 - 7

3.2 - 3

1.7 - 2

Add those up and you get 16

3 0
3 years ago
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I need help with this please
zheka24 [161]
Number 2




Step by step:


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3 0
3 years ago
A doctor wants to estimate the mean HDL cholesterol of all​ 20- to​ 29-year-old females. The number of subjects needed to estima
Ludmilka [50]

Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

8 0
3 years ago
A state offers two lottery games, WinOne and PlayBall. Both games cost $2 per ticket.
uysha [10]
In this question, both tickets cost 2$ per ticket.
The answer to this question would be: $0

In WinOne scenario, you need to match a ticket that has to pick from A-J(10 possibilities) and 0-9 (10 possibilities). The chance to win would be: 1/10* 1/10= 1/100

The expected value must be:
E= chance to win * win amount - ticket price
E= 1//100*$200 - $2= $2-$2= 0
8 0
3 years ago
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