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leva [86]
1 year ago
13

A shop has this offer.

Mathematics
1 answer:
BARSIC [14]1 year ago
8 0
49x3= 147 so 10 reduction will make tim spend 137. 49x5= 245 so 20 reduction will make Craig spend 225. 225-147= 78 so Craig spends 78£ more than tim. All the offers state “X or Y” meaning it’s one or the other hence the ‘or’. Atleast that’s my interpretation of it.
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The length of a tiger is 45in the head is 10in. What equation can find the length of the rest of the body?
creativ13 [48]

Answer:

45in - 10in = 35in

Step-by-step explanation:

please mark me as brainliest!

3 0
3 years ago
What is the location of the point on the number line that is 2/5 of the way from A = -6 to B = 9
sammy [17]
The distance between is =|9|+|-6|=15.
We can find that
\frac{2}{5}  \times 15 = 6
So 2/5 of the AB segment is 6 distance points away from A at point C=0.

5 0
3 years ago
What is the sum of the zeros of the function: y= x^2 - 5x + 6?
yawa3891 [41]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y = 0

Quadratic formula

x = [5 ± √(5² – 4·1·6)] / [2·1]

 = [5 ± √1] / 2

 = [5 ± 1] /2

 = 2, 3

sum of zeros = 5

7 0
3 years ago
Identify the ordered pair that represents the vector from a(-9,9) to b(7,3) and the magnitude of ab.
sveta [45]

Answer:

Answers below

Step-by-step explanation:

1. Order pair method

[(x2-x1) , (y2-y1)] = b-a = [(7--9) , (3-9)] = (16,-6)

2. Magnitude

|v| = \sqrt{16^2+-6^2}

v = |17.088|

7 0
3 years ago
Read 2 more answers
Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ
Amanda [17]
So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}
7 0
2 years ago
Read 2 more answers
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