Note:xy means x times y and x(y) means the same thing
so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0
squareroot(y-1)+3=y
isolate the squareroot
subtrac 3 from boht sides
squareroot(y-1)=y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5
0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0
therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work
let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true
y=5
-1/3. Use the formula x1-x2/y1-y2
<span>-3|15 - s| + 2s^3 when s = -3 is
</span>-3|15 - (-3)| + 2(-3)^3 = <span>-3|15 + 3| + 2(-27) = </span><span>-3|18| + (-54) = -3(18) - 54 = -54 - 54 = -108</span>
<span>The least common multiple of x² – 8x + 12 and x² – x – 2.
by factoring:
∴ </span><span>x² – 8x + 12 = (x-2)(x-6)
</span><span>x² – x – 2 = (x-2)(x+1)
note: the factor (x-2) is common between them take it one time
∴ LCM = (x-2)(x-6)(x+1)
</span>
Hey there!!!
Given equation - 3x+6y
x is given as -3
y is given as 6
Plugin these values to get the final answer
3 ( -3 ) + 6 ( 6 )
-9 + 36
= 27
27 is the final and the required answer
Hope my answer helps!
