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never [62]
2 years ago
6

16-2t=3/2t+9 solve for t

Mathematics
1 answer:
In-s [12.5K]2 years ago
7 0

answer: t=2

steps:

16-2t = 3/2t+9

7 = 3/2t + 2t

2 is 4/2

7 = 3/2t + 4/2t

7 = 7/2t

7/2t = 7

(2/7)7/2t=7(2/7)

t=7(2/7)

t=2

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Step-by-step explanation:

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Step-by-step explanation:

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An adult takes 800 mg of ibuprofen. Each hour, the amount of ibuprofen in the person's
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Answer:

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Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

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(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

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Match coefficients,

A+B = 0 ..................(1)

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substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

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A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

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