No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
Answer:
The area of the regular hexagon is 
Step-by-step explanation:
we know that
The area of a regular hexagon can be divided into 6 equilateral triangles
so
step 1
Find the area of one equilateral triangle
we have
----> is the apothem
substitute
step 2
Find the area of 6 equilateral triangles
Line joining (-3, -1) and (1/2, 2)
Point point form for a line is
(c-a)(y-b) = (d-b)(x-a)
(1/2 - - 3)(y - -1) = (2 - -1)(x - -3)
(7/2)(y+1)=3(x+3)
7(y+1)=6(x+3)
7 - 6(3) = 6x - 7y
6x - 7y = -11
Answer: second choice, 6x - 7y = -11
Answer:
length=16feet width=12feet
Step-by-step explanation:
This may not be the best way, i just stumbled upon the answer using this.
I knew 14*14=196, which is relatively close to 192.
Then, I took away 2 from one of the 14s and added it to the other 14.
14-2=12 14+2=16
Apparently, 16*12 is 192, so that's the answer.
What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
Angle 2 = 30°
What we are looking for:
Toby's Angle = ?
The distance x = ?
We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.
Solving for Toby's Angle:
We know for a fact that the sum of all the angles of a triangle is 180°; therefore,
180° - (Side 1 + Side 2) = Toby's Angle
Toby's Angle = 180° - (40° + 30°)
Toby's Angle = 110°
Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
</span>
x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44
x = √4804.56
x = 69.31m
∴The distance, x, between two landmarks is 69.31m
