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Leviafan [203]
3 years ago
12

Write the algebraic expression for 4 more than the product of 7 and a number

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0
7n + 4

Ask if you want me to elaborate 
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Kennedy can type 150 words in 2 minutes. How many words per minute can Kennedy type?
zubka84 [21]

Answer:

75

Step-by-step explanation:

6 0
2 years ago
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Part A - Identify the outlier 3,52,54,64,69,71,77,79,82,88 Part B - Calculate the mean and median with the outlier. Part C - Cal
Anna71 [15]
The outlier is 3, and the outlier has a greater effect on the mean because it is an average of all numbers where as the median is just the middle value in the data set. Everything else you can do on your own. To find the mean you add all the numbers up and divide by the total amount of numbers there are, the median you just cross one out from the left and then cross one out from the right and continue doing this until you are left with one number, or if you are left with two numbers you can add those two numbers up and then divide them by 2
7 0
3 years ago
As a small step to save the environment, Luna came up with an idea for her sweet shop. In exchange for five eclaire boxes, that
svet-max [94.6K]

Answer: 15

Step-by-step explanation:

From the question, we can infer from the information given that:

5 eclaires boxes = 1 free eclaires box.

Therefore, to get the number of eclaires boxes that the kids will get if they bring 77 eclaires boxes, we have to divide 77 by 5 and this will be:

= 77 / 5

= 15.4

= 15

The group of kids will receive 15 free boxes

5 0
3 years ago
Which of the following has a solution set of {x | x = 0}?
Oliga [24]
Middle option.

<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)

If you work both sides separately you get

</span>(x  ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to 

</span><span>{x | x = 0}</span>
3 0
2 years ago
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What is the radical form of the expression (2x^4y^5)^3/8
s344n2d4d5 [400]

We are given expression: (2x^4y^5)^{3/8}

Let us distribute 3/8 over exponents in parenthesis, we get

(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})

= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )

Now, we could write inside expression of parenthesis in radical form.

xy\sqrt[8]{2x^{3}x^4y^7}

8 0
3 years ago
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