have 22 more questions and need help will give brainliest to the correct answer and plz explain how u got that answer

Mathematics

1 answer:

yarga [219]3 years ago

3 0

The final answer is A, or 1.25. If you'd like to see the steps, then read below.

First, plug in all of the known information. 2(18) + 2(1.5) + x = 10 + 30.25.
You get this equation because only one ticket costs 18 dollars so you multiply 18 by 2. Same thing with the ice cream. Using x as a variable for the soda since it is the unknown value. The total cost for Amy was 10 dollars and the total cost for Mike was 30.25 dollars. First, simplifying the parentheses using the order of pemdas, 2(18) = 36. 2 x 1.5 = 3. The equation now simplifies down to
36 + 3 + x = 10 + 30.25. Now adding together 36 and 3 you get
39 + x = 10 + 30.25. Now finally adding together 10 and 30.25, the total cost is 40.25. The equation now simplifying down to 39 + x = 40.25, the final step is to subtract 39 from 40.25 to isolate x. 40.25 - 39 = 1.25.
The soda costs 1.25 dollars.

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A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul

pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

$\hat p$ = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.6858

n = sample of respondents = 2,610

p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at

2.5% level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]