Suppose, we are given
two points as
F as (x1, y1)
H as (x2, y2)
assume it divides in m/n
we can use formula
now, we are given points as
F=(x1, y1)=(4,8)
H=(x2, y2)=(10,12)
so,
now, we can find
so, point is
.................Answer
Olamami performancematters.com/ola/lapichentCodes Miamidade
1 answer:
You might be interested in
Answer:
Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.
To prove: Point A,D,P are collinear.
Proof:
→Case 1. When vertices A and P are opposite side of Base BC.
In Δ ABD and Δ ACD
AB= AC [Given]
AD is common.
BD=DC [median of a triangle divides the side in two equal parts]
Δ ABD ≅Δ ACD [SSS]
∠1=∠2 [CPCT].........................(1)
Similarly, Δ PBD ≅ Δ PCD [By SSS]
∠ 3 = ∠4 [CPCT].................(2)
But, ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]
2 ∠2 + 2∠ 4=360° [using (1) and (2)]
∠2 + ∠ 4=180°
But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.
So, point A, D, P lies on a line.
CASE 2.
When ΔABC and ΔPBC lie on same side of Base BC.
In ΔPBD and ΔPCD
PB=PC[given]
PD is common.
BD =DC [Median of a triangle divides the side in two equal parts]
ΔPBD ≅ ΔPCD [SSS]
∠PDB=∠PDC [CPCT]
Similarly, By proving ΔADB≅ΔADC we will get, ∠ADB=∠ADC[CPCT]
As PD and AD are medians to same base BC of ΔPBC and ΔABC.
∴ P,A,D lie on a line i.e they are collinear.
Using an exponential function, it is found that the half-life of the substance is of 5.23 units of time.
<h3>What is the exponential function for the amount of a substance?</h3>The function is given by:
In which:
- A(0) is the initial value.
- k is the exponential decay rate.
The parameters are given by:
A(0) = 48, k = 0.1325.
Hence the equation is:
The half-life is the amount of time for which A(t) = 0.5A(0) = 24, hence:
t = 5.23.
More can be learned about exponential functions at brainly.com/question/25537936
#SPJ1
Answer:
Step-by-step explanation:
we are given some scenerios and we are to find out the total number of ways after mentioning permutations, combinations, or neither
a. How many ways can a coach choose two co-captains from 16 players in the basketball team?
Combination because both are having same position so order does not matter
16C2 = 120
b. In how many ways can seven questions out of ten be chosen on an examination?
Combinations because order of question does not matter.
10C7 = 10C3 = 120
c. Find the number of ways that 10 women in the finals of the skateboard street competition can finish first, second, and third in the X Games final.
Here order matters. Hence permutation
10P3 = 720
d. A postal zip code contains five digits. How many different zip codes can be made with the digits 0–9? Assume a digit can be repeated.
Here repitition is allowed. So neither permutation nor combination.
No of ways =