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2 years ago

How do you work this equation? x² + x - 30 = 0

Mathematics

2 answers:

Mariana [72]2 years ago

6 0

Answer:

x = 5 , x = - 6

Step-by-step explanation:

First we factor using factorisation method :

We need 2 numbers that multiply to give +1 and add to give -30 :

To find these numbers we write out all the factors of 30 :

1, 30

2 , 15

3 , 10

5 , 6 ----> These must be the numbers as -5+6 = 1

Now we split +x into -5x and +6x :

x² -5x + 6x -30 = 0

Factor the first 2 terms together and the last two terms :

x(x-5) + 6(x-5) = 0

Keep 1 bracket and terms outside the brackets collect them into one:

(x-5)(x+6) = 0

We know that 1 of these brackets must be equal to zero as anything multiplied by zero = 0

Either x - 5 =0 OR x + 6 = 0

So x = 5 x = - 6

These are our final answers

Hope this helped and have a good day

Tanzania [10]2 years ago

6 0

Answer:

(x-5) (x+6)

x=5

X=-6

Step-by-step explanation:

x²+x-30=0

factorizing

x²-5x+6x-30=0

x(x-5)+6(x-5) =0

(x-5)(x+6)=0

now solve individually

x-5=0

send 5 to the other side

x=5

x+6=0

send 6 to the other side

x=-6

hope you understand the procedure

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3 years ago

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Slav-nsk [51]

Answer:

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Step-by-step explanation:

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2 years ago

Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = 10x^5 + 8x^4 - 15x^3 +2x^2 - 2

vagabundo [1.1K]

Given:

The function is:

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

To find:

All the possible rational zeros for the given function by using the Rational Zero Theorem.

Solution:

According to the rational root theorem, all the rational roots are of the form $\dfrac{p}{q},q\neq 0$ , where p is a factor of constant term and q is a factor of leading coefficient.

We have,

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

Here,

Constant term = -2

Leading coefficient = 10

Factors of -2 are ±1, ±2.

Factors of 10 are ±1, ±2, ±5, ±10.

Using the rational root theorem, all the possible rational roots are:

$x=\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

Therefore, all the possible rational roots of the given function are $\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

5 0

3 years ago

-3(x+8)-12=62-24 solve

Juli2301 [7.4K]

Answer:

First we chose one side to solve.

I am doing the one on the left first.

so -3x+-24-12

-3x-12

Now we do the other side

62-24 is

38 therefore

-3x-12=38

4 0

3 years ago

Direction: Answer the following problem sets. Please include what is the given, asked, formula, solution and final answer with u

olga2289 [7]

Answer:

7.5s

1.6666 repeating or 1.67 m/s²

Step-by-step explanation:

the equation you have to use is Vfinal=Vstart+acceleration•time

(I'm gonna simplify to Vf=Vs+at)

so you gotta rework it for the two equations

for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at

then divide acceleration on both sides to get t=(Vf–Vs)/a

for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)

so you the plug in

(I don't put the units in to the problem unless needed)

1. t=(Vf–Vs)/a to t=(0–30)/-4.0

t= -30/-4.0

t=7.5 seconds

2. a=(Vf–Vs)/t to a=(10–0)/6.0

a= 10/6.0

a= 1.67m/s²

(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)

8 0

3 years ago