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kirza4 [7]
3 years ago
15

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

-2\rightarrow 16\div(-8)

-3\rightarrow -2\frac{2}{5}\div \frac{4}{5}

3\rightarrow 3\frac{3}{7}\div 1\frac{1}{7}

2\rightarrow -12.2\div (-6.1)

Step-by-step explanation:

1.-2\frac{2}{5}\div\frac{4}{5}

Change mixed fraction term into simple fraction

-\frac{12}{5}\div \frac{4}{5}

When we change divide into multiply then term on right hand of divide will be reciprocal.

-\frac{12}{5}\times \frac{5}{4}=-3

2.-12.2\div (-6.1)

\frac{-12.2}{-6.1}=\frac{2\times (-6.1)}{-6.1}=2

Hence, -12.2\div -6.1=2

3.3\frac{3}{7}\div 1\frac{1}{7}

\frac{24}{7}\div \frac{8}{7}

When we change divide into multiply then term on right hand of divide will be reciprocal.

\frac{24}{7}\times \frac{7}{8}=3

4.16\div(-8)

\frac{16}{-8}=-2

Degger [83]3 years ago
3 0

Answer:

1 = B

2 = A

3 = C

4 = D

Step-by-step explanation:

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

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The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

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The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

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A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

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By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

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The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

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Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

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