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2 years ago

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⚠️⚠️⚠️⚠️ Help Mhanifa! XXXXTRA Points! Please I really need help on my math. No links please! Quality answer please! Answer all

parts to the question. Thanks in advance. ⚠️⚠️⚠️⚠️

1 answer:

Hoochie [10]2 years ago

7 0

Answer:

36 units

Step-by-step explanation:

<u>Top base:</u>

a = 6 units

<u>Left leg:</u>

b = 8 units

<u>Bottom base:</u>

d = 12 units

<u>Right leg:</u>

c² = √6²+8² = √100
c = 10 units

<u>Perimeter:</u>

P = 6 + 8 + 10 + 12 = 36 units

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HELP!! ASAP PLEASE!! WILL GIVE BRAINLIEST!!

patriot [66]

Answer:

6^-4 ÷ 3^-4

6^-4/3^-4

Since their powers are negative

Flip them both so the negative index is lost.

It now becomes

3^4/6^4

81/1296

=1/16

6 0

2 years ago

PLEASE HELP ASAP !!

wariber [46]

Answer:

<u>First figure:</u> $954cm^3$

<u>Second figure:</u> $1,508yd^3$

<u>Third figure:</u>

Height= q
Side length = r

<u>Fourth figure: </u> $726cm^3$

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

$\text{Volume of a cylinder}=\pi \times radius^2\times length$

<u>2. Data:</u>

radius = 9cm / 2 = 4.5cm

length = 15 cm

<u>3. Substitute in the formula and compute:</u>

$Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3$

<u>B. Second figure</u>

<u>1. Formula: </u>

$\text{Volume of a leaned cylinder}=\pi \times radius^2\times height$

<u>2. Data:</u>

radius = 12yd

height = 40 yd

<u>3. Substitute and compute:</u>

$Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3$

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

$Volume=(1/3)B\times H$

<u>2. Data: </u>

height: H = 18cm

side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

$\text{Area of the base}=B=(11cm)^2=121cm^2$

b) <u>Volume of the pyramid</u>:

$Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3$

4 0

3 years ago

Read 2 more answers

Josh has 4 times as many pears as leya, who has one half as many pears as amy. If josh has 32 pears how many does amy have?

arlik [135]

<h3>The number of pears Amy has is 16.</h3>

Step-by-step explanation:

Let J represent the number of pears Josh has.

Let L represent the number of pears Leya has.

Let A represent the number of pears Amy has.

From the question given above,

Josh (J) = 4 × Leya (L)

J = 4L ....... (1)

Leya (L) = ½ × Amy (A)

L = ½A ........ (2)

Next, we shall determine the number of pears Leya has. This can be obtained as follow:

From equation 1

J = 4L

But

Josh (J) = 32 pears

Thus,

32 = 4L

Divide both side by 4

L = 32 / 4

<h3>Leya (L) = 8 pears </h3>

Finally, we shall determine the number pears Amy has. This can be obtained as follow:

From equation 2

L = ½A

But

Leya (L) = 8 pears

Thus,

8 = ½A

Cross multiply

A = 8 × 2

<h3>Amy (A) = 16 pears </h3>

Therefore, Amy has 16 pears.

Learn more: brainly.com/question/20971657

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2 years ago

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Graph step by step:<br> f(x)=-2x+1

Paul [167]

Step-by-step explanation:

Root:(1/2, 0)

Domain: x∈R

Range: y∈R

Vertical intercept: (0, 1)

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2 years ago

V=1/2at^2 solve for t

malfutka [58]

$\dfrac{1}{2}at^2=V\qquad\text{multiply both sides by 2}\\\\at^2=2V\qquad\text{divide both sides by}\ a\neq0\\\\t^2=\dfrac{2V}{a}\to\boxed{t=\sqrt{\dfrac{2V}{a}}}$

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3 years ago