1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
forsale [732]
3 years ago
11

Pls help me tysmmmm~

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0
Yes let’s go ahead with me a few days and
You might be interested in
3/2000 as a decimal
Anarel [89]

<span>Decimal</span>

<span>
</span>

<span>3/2000 = 0.0015</span>

4 0
3 years ago
an umbrella at a shop was marked for $6. during a slae a discount of 10% was given. A further 8% discount was given to senior ci
Ierofanga [76]

Answer:

75

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
the sum of the reversed number and the original number is 154. Find the original number, if the ones digit in it is 2 less than
VladimirAG [237]

Answer:

The number is 86

Step-by-step explanation:

Let the number be  xy, then the reverse is yx

The sum of the reversed number and the original number is 154,

\implies (10x+y)+(10y+x)=154

We simplify this to get:

\implies 11x+11y=154....eqn(1)

If the ones digit in it is 2 less than the tens digit, then

y=x-2....eqn(2)

Putt equation (2) in (1)

\implies 11x+11(x-2)=154

\implies 11x+11x-22=154

\implies 11x+11x=154+22

\implies 22x=176

\implies x=8

Put x=8 in the second equation:

y=8-2=6

The original number is 86

7 0
3 years ago
Read 2 more answers
I need help please. Thanks!
Karolina [17]

Answer:

A

Step-by-step explanation:

We are given the function f and its derivative, given by:

f^\prime(x)=x^2-a^2=(x-a)(x+a)

Remember that f(x) is decreasing when f'(x) < 0.

And f(x) is increasing when f'(x) > 0.

Firstly, determining our zeros for f'(x), we see that:

0=(x-a)(x+a)\Rightarrow x=a, -a

Since a is a (non-zero) positive constant, -a is negative.

We can create the following number line:

<-----(-a)-----0-----(a)----->

Next, we will test values to the left of -a by using (-a - 1). So:

f^\prime(-a-1)=(-a-1-a)(-a-1+a)=(-2a-1)(-1)=2a+1

Since a is a positive constant, (2a + 1) will be positive as well.

So, since f'(x) > 0 for x < -a, f(x) increases for all x < -a.

To test values between -a and a, we can use 0. Hence:

f^\prime(0)=(0-a)(0+a)=-a^2

This will always be negative.

So, since f'(x) < 0 for -a < x < a, f(x) decreases for all -a < x < a.

Lasting, we can test all values greater than a by using (a + 1). So:

f^\prime(a+1)=(a+1-a)(a+1+a)=(1)(2a+1)=2a+1

Again, since a > 0, (2a + 1) will always be positive.

So, since f'(x) > 0 for x > a, f(x) increases for all x > a.

The answer choices ask for the domain for which f(x) is decreasing.

f(x) is decreasing for -a < x < a since f'(x) < 0 for -a < x < a.

So, the correct answer is A.

3 0
2 years ago
What's the missing angle??
ruslelena [56]
Missing angle = 100
Because Corresponding Angles<span> are equal on </span><span>Parallel Lines</span>
4 0
3 years ago
Other questions:
  • Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
    11·1 answer
  • Use the definition of the derivative to find f'(x) for f(x)=3x^2-5x+2
    12·1 answer
  • -8 + (-4)<br> please help me find the answer 20 pts
    13·2 answers
  • The polynomial equation x^3+x^2=-9x-9 has complex roots +/-3i What is the other root? Use a graphing calculator and a system of
    7·1 answer
  • Using the Chinese Remainder Theorem, solve the congruence<br> x 15 (mod 42)<br> x 5 (mod 19)
    5·1 answer
  • Divide p(x) = x4 + 6x3 + 7x2 − 6x − 8 by x + 4 and by x − 3 to find the remainder in each case. Make sure to use the remainder t
    13·1 answer
  • Draw a box-and-whisker plot of the data. 37, 34, 26, 33, 38, 36, 30
    13·1 answer
  • Convert 0.6 radians to degree measure.<br> Round your answer to the nearest hundredth.
    12·2 answers
  • PLEASE ANSWER ASAP !!!! Y
    12·2 answers
  • What is 832 times 1 equal to?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!