1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
posledela
2 years ago
7

: A freeway exit ramp has a single lane and consist of entirely of a horizontal curve with a central angle of 90 degree and a le

ngth of 626 ft. If the distance cleared from the centre line for sight distance is 19.4ft, what design speed was used? Assumptions: t= 2.5sec, f=0.4
Engineering
1 answer:
Mariana [72]2 years ago
4 0

The design speed was used for the freeway exit ramp is 11 mph.

<h3>Design speed used in the exit ramp</h3>

The design speed used in the exit ramp is calculated as follows;

f = v²/15R - 0.01e

where;

  • v is designated speed

v = ωr

v = (θ/t) r

θ = 90⁰ = 1.57 rad

v = (1.57 x 19.4)/2.5 s

v = 12.18 ft/s = 8.3 mph

<h3>Design speed</h3>

f = v²/15R - 0.01e

let the maximum superelevation, e = 1%

f = (8.3)²/(15 x 19.4) - 0.01

f = 0.22

0.22 is less than value of f which is 0.4

<h3>next iteration, try 10 mph</h3>

f = (10)²/(15 x 19.4) - 0.01

f = 0.33

0.33 is less than 0.4

<h3>next iteration, try 11 mph</h3>

f = (11)²/(15 x 19.4) - 0.01

f = 0.4

Thus, the design speed was used for the freeway exit ramp is 11 mph.

Learn more about design speed here: brainly.com/question/22279858

#SPJ1

You might be interested in
Quantitative meaning
pychu [463]

Answer:

Explanation:

relating to, measuring, or measured by the quantity of something rather than its quality.Often contrasted with qualitative.

6 0
3 years ago
Read 2 more answers
Which two statements about professional technical jobs in the energy industry are correct?
Tanya [424]
The answer is both B and D
4 0
3 years ago
Read 2 more answers
Air flows through a rectangular section Venturi channel . The width of the channel is 0.06 m; The height at the inlet (1) and ou
nataly862011 [7]

Answer:

a) Q = 1.3044 m^3 / s

b) h2 = 0.37 m

c) Pi = Pe = Patm = 101.325 KPa

Explanation:

Given:-

- The constant width of the rectangular channel, b = 0.06 m

- The density of air, ρa = 1.23 kg/m^3

- The density of water, ρw = 1000 kg / m^3

- The height of the channel at inlet and exit, hi = he = 0.04 m

- The height of the channel at point 2 = h2

- The height of the channel at point 3 - Throat , ht = 0.02 m

- The change height of the water in barometer at throat, ΔHt = 0.1 m

- The change height of the water in barometer at point 2, ΔH2 = 0.05 m  

- The flow rate = Q

Solution:-

- The flow rate ( Q ) of air through the venturi remains constant because the air is assumed to be incompressible i.e ( constant density ). We have steady state conditions for the flow of air.

- So from continuity equation of mass flow rate of air we have:

                         m ( flow ) = ρa*An*Vn = Constant

Where,

             Ai : The area of the channel at nth point

             Vi : The velocity of air at nth point.

- Since, the density of air remains constant throughout then we can say that flow rate ( Q ) remains constant as per continuity equation:

                        Q = m ( flow ) / ρa

Hence,

                        Q = Ai*Vi = A2*V2 = At*Vt = Ae*Ve

- We know that free jet conditions apply at the exit i.e the exit air is exposed to atmospheric pressure P_atm.

- We will apply the bernoulli's principle between the points of throat and exit.

Assuming no changes in elevation between two points and the effect of friction forces on the fluid ( air ) are negligible.

                       Pt + 0.5*ρa*Vt^2 = Pe + 0.5*ρa*Ve^2

- To determine the gauge pressure at the throat area ( Pt ) we can make use of the barometer principle.

- There is an atmospheric pressure acting on the water contained in the barometric tube ( throat area ). We see there is a rise of water by ( ΔHt ).

- The rise in water occurs due to the pressure difference i.e the pressure inside the tube ( Pt ) and the pressure acting on the water free surface i.e ( Patm ).

- The change in static pressure leads to a change in head of the fluid.

Therefore from Barometer principle, we have:

              Patm - Pt-abs = pw*g*ΔHt

              101,325 - Pt-abs = 1000*9.81*0.1

              Pt-abs = 101,325 - 981

              Pt-abs = 100,344 Pa ..... Absolute pressure

- We will convert the absolute pressure into gauge pressure by the following relation:

             Pt = Pt-abs - Patm

             Pt = 100,344 - 101,325

             Pt = -981 Pa  ... Gauge pressure  

- Now we will use the continuity equation for points of throat area and exit.

            At*Vt = Ae*Ve

            b*ht*Vt = b*he*Ve

            Ve = ( ht / he ) * Vt

            Ve = ( 0.02 / 0.04 ) * Vt

            Ve = 0.5*Vt

           

- Now substitute the pressure at throat area ( Pt ) and the exit velocity ( Ve ) into the bernoulli's equation expressed before:

            Pt + 0.5*ρa*Vt^2 = 0 + 0.5*ρa*( 0.5*Vt )^2

            -981  = 0.5*ρa*( 0.25*Vt^2 - Vt^2 )

            -981 = - 0.1875*ρa*Vt^2

            Vt^2 = 981 / ( 0.1875*1.23 )

            Vt = √4253.65853

            Vt = 65.22 m/s

- The flow rate ( Q ) of air in the venturi is as follows:

            Q = At*Vt

            Q = ( 0.02 )*( 65.22 )

            Q = 1.3044 m^3 / s   ..... Answer part a

- We will apply the bernoulli's principle between the points of throat and point 2.

Assuming no changes in elevation between two points and the effect of friction forces on the fluid ( air ) are negligible.

                       Pt + 0.5*ρa*Vt^2 = P2 + 0.5*ρa*V2^2

- To determine the gauge pressure at point 2 ( P2 ) we can make use of the barometer principle.

Therefore from Barometer principle, we have:

              Patm - P2-abs = pw*g*ΔH2

              101,325 - P2-abs = 1000*9.81*0.05

              P2-abs = 101,325 - 490.5

              Pt-abs = 100834.5 Pa ..... Absolute pressure

- We will convert the absolute pressure into gauge pressure by the following relation:

             P2 = P2-abs - Patm

             Pt = 100,344 - 100834.5

             Pt = -490.5 Pa  ... Gauge pressure            

- Now substitute the pressure at point 2 ( P2 )  bernoulli's equation expressed before:

            Pt + 0.5*ρa*Vt^2 = P2 + 0.5*ρa*( V2 )^2

            ( Pt - P2 ) + 0.5*ρa*Vt^2 = 0.5*ρa*( V2 )^2

            2*( Pt - P2 ) / ρa + Vt^2 = V2^2

            2*( -981 + 490.5 ) / 1.23 + 65.22^2 = V2^2

            -981/1.23 + 4253.6484 = V2^2

            V2 = √3456.08742

            V2 = 58.79 m/s

- The flow rate ( Q ) of air in the venturi remains constant is as follows:

            Q = A2*V2

            Q = b*h2*V2

            h2 = Q / b*V2  

            h2 = 1.3044 / ( 0.06*58.79)

            h2 = 0.37 m      ..... Answer part b

- We will apply the bernoulli's principle between the points of inlet and exit.

Assuming no changes in elevation between two points and the effect of friction forces on the fluid ( air ) are negligible.

                       Pi + 0.5*ρa*Vi^2 = Pe + 0.5*ρa*Ve^2

- Now we will use the continuity equation for points of inlet area and exit.

            Ai*Vi = Ae*Ve

            b*hi*Vi = b*he*Ve

            Vi = ( he / hi ) * Ve

            Vi = ( 0.04 / 0.04 ) * 0.5*Vt

            Vi = Ve = 0.5*Vt = 0.5*65.22 = 32.61 m/s

- Now substitute the velocity at inlet in bernoulli's equation expressed before:

            Pi + 0.5*ρa*Vi^2 = 0 + 0.5*ρa*( Ve )^2

           

Since, Vi = Ve then:

           Pi = Pe = 0 ( gauge pressure ).

           Pi = Pe = Patm = 101.325 KPa

Comment: If the viscous effects are considered then the Pressure at the inlet must be higher than the exit pressure to do work against the viscous forces to drive the fluid through the venturi assuming the conditions at every other point remains same.

8 0
3 years ago
What Is the Job Demand for Solar Engineers?<br> (2 or more sentences please and thank you)
podryga [215]

Answer:

repair of inverters and anything that has to do with solar energy...that is power from the sun

4 0
3 years ago
What are some paradigms from history that have been proven inaccurate or incomplete
frozen [14]
That the world is flat. Brainliest?
4 0
2 years ago
Other questions:
  • What is pessimism technology
    12·1 answer
  • Component(s) that only allow(s) electrons to flow in one direction. Mark all that apply
    15·1 answer
  • Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would y
    8·1 answer
  • Método de Programación lineal utilizado para resolver problemas en teoría de redes?
    15·1 answer
  • Excessive looseness in steering and suspension components can cause _____
    13·1 answer
  • What kinds of problems or projects would a mechanical engineer work on?
    11·1 answer
  • To understand the concept of moment of a force and how to calculate it using a scalar formulation.
    9·1 answer
  • Which of the following procedures best applies to assessing the embodied energy of a building?
    12·1 answer
  • Is there a project idea, or invention that would be good for<br> my class.
    6·2 answers
  • Which of the following is NOT an ASE certification? Select one:
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!