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bonufazy [111]
3 years ago
10

-1 1/6 divided by 2 1/3

Engineering
1 answer:
pantera1 [17]3 years ago
4 0

Answer:

-\frac{1}{2}

Explanation:

-1\frac{1}{6}:2\frac{1}{3}=\\  \\=-\frac{7}{6}:\frac{7}{3}\\  \\=-\frac{7}{6}*\frac{3}{7}\\  \\=-\frac{1}{2}

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Answer:

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Explanation:

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3 years ago
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aleksandr82 [10.1K]

Answer:

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5 0
2 years ago
A 10.2 mm diameter steel circular rod is subjected to a tensile load that reduces its cross- sectional area to 52.7 mm^2. Determ
VMariaS [17]

Answer:

The percentage ductility is 35.5%.

Explanation:

Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.

Step1

Given:

Diameter of shaft is 10.2 mm.

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Calculation:

Step2

Initial area is calculated as follows:

A=\frac{\pi d^{2}}{4}

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Step3

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