A programmable integrated circuit (PIC) is another name for a microcontroller.

A Newtonian fluid with a viscosity of 50 cP is placed between two large parallel separated by a distance of 8 mm. Each plate has

r-ruslan [8.4K]

Answer:

F= 5 N

V= 4 m/s

Explanation:

Given that fluid is Newtonian fluid .As we know that for Newtonian fluid the shear stress given as

$\tau =\mu \dfrac{du}{dy}$

We also know that

Force = shear stress x area of plate

Now by putting the values

$\tau =\mu \dfrac{du}{dy}$

Here velocity of fluid profile is linear.

$\tau =\mu \dfrac{U}{h}$

$\tau =50\times 10^{-2}\times 0.1\times \dfrac{0.4}{0.008}$

τ= 2.5 Pa

So force = 2.5 x 2

F= 5 N

Now when fluid is replaced by another fluid but force is constant.The height of plate is also constant.

Lets take velocity of fluid is V in the new condition

So we can say that

$\mu_1U=\mu_2V$

Now by putting the value

50 x 0.4 = 5 x V

V= 4 m/s

6 0

3 years ago

How do I give brainless?

lesya [120]

Answer:

hi friend

once two members had answered tour question there will be a yellow box of brainlist and press the any one person you want to mark brainlist and done

Explanation:

hope it helps

have a good day

4 0

2 years ago

Felix has placed some Copper wire (where the official looked up inferred absolute temperature is 234.5 Celsius) 28 gauge wire in

Kruka [31]

Answer:

2.14 ft

Explanation:

We will use the following equation:

$L = \frac{R_{T} * A}{p_{20C}*(1+\alpha _{20C}*dt ) }$

Data obtained:

$R_{15.3 F , -9.27 C} = 15.3 ohms\\A_{28-gauge} = 8.2*10^(-8) m^2\\p_{20 C} = 1.723*10^(-6)\\\alpha _{20C} = 0.00393\\ dt = 20 - (-9.27) = 29.28$

Using the above equation:

$L = \frac{15.3 * 8.2*10^(-8)}{1.723*10^(-6)*(1+0.00393*29.28 ) }\\\\L =0.6530 m = 2.14 ft$

5 0

3 years ago

If a hoist lifts a 4500lb load 30ft in 15s, the power delivered to the load is a) 18.00hp b) 9000hp c) 16.36hp d) None of the ab

12345 [234]

Answer:

Explanation:

load = 4500lb lift height= 30 ft

time =15 s

velocity= $\frac{30}{15}$ ft/s

velocity=2 ft/s

power = force $\times$ velocity

power= ${4500}\times2$

power= 9000 lb ft/s

1 hp= 550 lb ft/s

power= $\frac{9000}{550} =16.36$ hp

5 0

3 years ago

A spherical, stainless steel (k 16 W m1 K-1) tank has a wall thickness of 0.2 cm and an inside diameter of 10 cm. The inside sur

SOVA2 [1]

Answer:

the rate of heat loss is 2.037152 W

Explanation:

Given data

stainless steel K = 16 W $m^{-1}K^{-1}$

diameter (d1) = 10 cm

so radius (r1) = 10 /2 = 5 cm = 5 × $10^{-2}$

radius (r2) = 0.2 + 5 = 5.2 cm = 5.2 × $10^{-2}$

temperature = 25°C

surface heat transfer coefficient = 6 6 W $m^{-2}K^{-1}$

outside air temperature = 15°C

To find out

the rate of heat loss

Solution

we know current is pass in series from temperature = 25°C to 15°C

first pass through through resistance R1 i.e.

R1 = ( r2 - r1 ) / 4 $\pi$ × r1 × r2 × K

R1 = ( 5.2 - 5 ) $10^{-2}$ / 4 $\pi$ × 5 × 5.2 × 16 × $10^{-4}$

R1 = 3.825 × $10^{-3}$

same like we calculate for resistance R2 we know i.e.

R2 = 1 / ( h × area )

here area = 4 $\pi$ r2²

area = 4 $\pi$ (5.2 × $10^{-2}$ )² = 0.033979

so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979 )

R2 = 4.90499

now we calculate the heat flex rate by the initial and final temp and R1 and R2

i.e.

heat loss = T1 -T2 / R1 + R2

heat loss = 25 -15 / 3.825 × $10^{-3}$ + 4.90499

heat loss = 2.037152 W

8 0

3 years ago