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ArbitrLikvidat [17]
2 years ago
13

PLS HELPPP!!!! Look at pic

Mathematics
1 answer:
timama [110]2 years ago
4 0

The correct option regarding whether the equation x² = y² is a function is:

No, since if you solve the equation for x, then x = \pm y

<h3>What is needed for a relation to represent a function?</h3>

In a function, each value of x can be associated with only one value of y.

In this problem, the equation is:

x^2 = y^2

Then:

x = \pm \sqrt{y^2}

x = \pm \sqrt{y}

x is associated with two values, -\sqrt{y} and \sqrt{y}, hence it is not a function.

A similar problem, in which we verify if a relation is a function, is at  brainly.com/question/12463448

#SPJ1

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Write an equation of the line that passes through (4, −6) and is parallel to the line y=−3x−9.
Troyanec [42]

Answer:

56

Step-by-step explanation:

Strange question to me

6 0
3 years ago
PLEASE HELP!! If f (x) = 4x^-2 + 1/4x^2 + 4, then f’(2) =
Elena-2011 [213]
<h3>Answer: D) 0</h3>

Work Shown:

f(x) = 4x^(-2) + (1/4)x^2 + 4

f ' (x) = 4*(-2)x^(-3) + (1/4)*2x .... power rule

f ' (x) = -8x^(-3) + (1/2)x

f ' (2) = -8(2)^(-3) + (1/2)*(2)

f ' (2) = 0

4 0
3 years ago
The Report of the Presidential Commission on the Space Shuttle Challenger Accident in 1986 shows a plot of the calculated joint
laiz [17]

Answer:

NO, as per study, I cant see any other problem than the sample size in the procedure.

From the graph there is a slight quadratic relationship between temperature and number of O-rings.

As in the graph, we can see that above 50°F but below 55°F number of O-rings in 3 but after 55°F as temperature goes on increasing the number of O-rings decreases and remains constant up to 70°F and above 70°F the number of O-rings increases to 2. Hence, we can say that there is a relationship between temperature and number of O-rings.

If we want to fit a linear regression through these seven observations, the slope would be positive as linear regression line passes through the average.

Looking at the relationship, slope must be significantly different from zero as there is a relationship between two variables, where as slope significantly zero implies no relationship. However, we have only seven points so drawing a conclusion is difficult as the nature of the relationship is not clearly visualized by this graph.

8 0
4 years ago
Read 2 more answers
What is the square root of this problem?—-
musickatia [10]
<h2>Answer</h2>

The answer to this question is 0.9

<h2>Explanation</h2>

We know that

sequre of 9 is equal to 81  as 9^2 = 81

Then sequre of 0.9 will be

0.9^2 = 0.81

So,

b = \sqrt{ 0.81}

b = \sqrt{ 0.9^2}

Exponent and square root cancel out each other

So, the answer is 0.9.


4 0
4 years ago
How do I solve this?
pishuonlain [190]
Good morning! So, what this question wants us to do is find each y value given its x value. Without the function it gives us already, this would be pretty difficult.
It gives us a function rule of y=2x+3. This means that we need to plug in each x value into the equation and solve for y. Let’s work on these first three.

y=2x+3} x=-4
y=2(-4)+3
y=-8+3
y=-5
So, if x=-4, then y=-5.

y=2x+3} x=-2
y=2(-2)+3
y=-4+3
y=-1
So, if x=-4, then y=-1.

y=2x+3} x=0
y=2(0)+3
y=0+3
y=3
So, if x=0, then y=3.

Try out the last one, and if you have any questions, comment below! Here are some extra x values if you need more practice.
Using the same function rule, y=2x+3, try to find the y value if x=-6, x=-3, x=5, or x=6.
8 0
3 years ago
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