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Sladkaya [172]
3 years ago
15

What is the square root of this problem?—-

Mathematics
1 answer:
musickatia [10]3 years ago
4 0
<h2>Answer</h2>

The answer to this question is 0.9

<h2>Explanation</h2>

We know that

sequre of 9 is equal to 81  as 9^2 = 81

Then sequre of 0.9 will be

0.9^2 = 0.81

So,

b = \sqrt{ 0.81}

b = \sqrt{ 0.9^2}

Exponent and square root cancel out each other

So, the answer is 0.9.


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Answer:

Step-by-step explanation:

Function f(x)=|x| is transformed to create function g(x)=|x+4|+3. What transformations are performed to function f to get function g? Select each correct answer.

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2 years ago
Please help me: w+7/8=3/4 Show you're work
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Step-by-step explanation:

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8 0
3 years ago
Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

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3 years ago
What is the product of seven plus two and eight minus two
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