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nignag [31]
2 years ago
15

Please use elimination method to solve

Mathematics
2 answers:
Lostsunrise [7]2 years ago
8 0

Answer:

(4, - 1 )

Step-by-step explanation:

2x + 7y = 1 → (1)

3x + 4y = 8 → (2)

multiplying (1) by 3 and (2) by - 2 and adding will eliminate x

6x + 21y = 3 → (3)

- 6x - 8y = - 16 → (4)

add (3) and (4) term by term to eliminate x

0 + 13y = - 13

13y = - 13 ( divide both sides by 13 )

y = - 1

substitute y = - 1 into either of the 2 equations and solve for x

substituting into (1)

2x + 7(- 1) = 1

2x - 7 = 1 ( add 7 to both sides )

2x = 8 ( divide both sides by 2 )

x = 4

solution is (4, - 1 )

vagabundo [1.1K]2 years ago
7 0

The answer is x = 4, y = -1 or (4, -1).

We are given :

  1. <u>2x + 7y = 1</u>
  2. <u>3x + 4y = 8</u>

<u />

Multiply the 1st equation with 3 and 2nd equation with 2.

<u>3. 3(2x + 7y) = 3(1) ⇒ 6x + 21y = 3</u>

<u>4. 2(3x + 4y) = 2(8) ⇒ 6x + 8y = 16</u>

<u />

Now, subtract : Equation 3 - Equation 4.

  • 6x + 21y - 6x - 8y = 3 - 16
  • 13y = -13
  • y = -1

Substitute in the 1st equation.

  • 3x + 4(-1) = 8
  • 3x - 4 = 8
  • 3x = 12
  • x = 4
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