Question

Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.

Answer 1

By applying Pythagoras theorem, the missing segment lengths of this triangles include:

1. CD = 10√2
2. AC = 10√2
3. BC =  10
4. AB = 10

How to find the missing segment lengths?

Since triangle ACD is a right-angle triangle, we would use Pythagoras theorem to find the missing segment lengths of this triangles as follows:

c² = a² + b² ≡ AD² = CD² + AC²

Next, we would use cos trigonometric ratio to find side CD,

cos45 = adjacent/hypotenuse

cos 45 = CD/20

1/√2 = CD/20

CD = 1/√2 × 20

CD = (20√2)/2

CD = 10√2

For side AC, we have:

AD² = CD² + AC²

AC² = AD² - CD²

AC² = 20² - (10√2)²

AC² = 400 - 100(2)

AC = √200

AC = 10√2

From triangle ABC, we have:

cos45 = BC/10√2

BC = 10√2 × cos45

BC = 10√2 × 1/√2

BC = (10√2)/√2

BC = 10

For side AB, we have:

AB² = (10√2)² - 10²

AB² = 200 - 100

AB² = 100

AB = 10.

Read more on Pythagorean theorem here: brainly.com/question/23200848

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